使用Python将美分转换为25美分、5美分、1美分和1美分

Question

我正在使用Python，我试图将一定数量的以美分为单位的货币转换成25美分、5美分、1美分和1美分的等值货币。在

这是我目前所拥有的，但我发现问题是我不知道如何从硬币中取出剩余的硬币，然后把它分解成一角硬币、五分镍币和一分硬币。我是新手，只是日子不好过。我不是要求别人来解决问题，只要指出我做错了什么（也许我需要做些什么来解决它）。在

# Convert some money to an appropriate collection of cents
penny = 1
nickel = 5
dime = 10
quarter = 25

quarters = 0
dimes = 0
nickels = 0
pennys = 0

cents = int(input("Please enter an amount of money you have in cents: "))

if cents >= 25:
    quarters = cents / quarter
    cents % quarter
if cents >= 10:
    dimes = cents/dime
    cents % dime
if cents >= 5:
    nickels = cents /nickel
    cents % nickel
if cents > 0:
    pennys = cents / penny
    cents = 0

print ("The coins are: quarters", quarters,\
",dimes", dimes, ",nickels", nickels, ", and pennys.", pennys)

Answer 1

昨天晚上一直在挣扎。是的，你需要除法和模。不是最像Python的方式，但它对任何数量都有效，当你把你可以输入自动售货机的美元金额限制在5美元时。这个问题一直被问到，却一直被忽视。也许是因为它是家庭作业。。。不管怎样。。。。在

def vending_machine_change():
    cost = float(input("Enter cost of item: "))
    change= 5.00-cost
    dollars = int(change)
    quarters_change= float("%.2f" % ((change-dollars)))
    quarters =int(quarters_change/0.25)
    dime_change= float("%.2f" % (quarters_change%0.25))
    dimes=int(dime_change/0.10)
    nickel_change = float("%.2f" % (dime_change%0.10))
    nickels= int(nickel_change/0.05)
    pennys = int(nickel_change*100)
    print("Change amount: " + str((dollars)) + ' Dollars, ' + str((quarters)) + ' Quarters, '+ str((dimes)) + ' Dimes, '+ str((nickels)) + ' Nickels, '+ str((pennys)) + ' Pennies' )
    pass