当我将状态设置为false时，为什么程序没有跳出while循环？

Question

我是python的新手，我只是在创建一个简单的随机数猜测游戏

简单地说，要跳出while循环，用户必须猜测正确的数字或达到最大尝试次数，即3次

但是，当我调用函数检查尝试次数时，代码似乎没有中断循环。有没有办法从调用函数的while循环中解脱出来

import random 
print("*** RANDOM NUMBER GUESSING ***\n")
print("1. Guess the number between x and y.")
print("2. You have 3 attempts to guess the random number.\n")

x = input("The random number is generated between x: ")
x = int(x)
y = input ("and y: ")
y = int(y)

#Random number generated
randNum = random.randint(x,y)

userAttempts = 0
gameState = True

#Function checking the attempts made
#If max attempts reached then gameState = False to break out of the while loop
def maxAttempts(attempts, state):
    if attempts == 3:
        print("Max attempts reached!")
        state = False
        return state


while gameState:
    userNum = input("Guess the random: ")
    userNum = int(userNum)

    if userNum == randNum:
        print("Well done you guessed the correct number !!")
        gameState = False;
    elif userNum > randNum:
        print("Number is too high")
        userAttempts += 1
        maxAttempts(userAttempts, gameState)

        #debugging
        print("Attempts: ", userAttempts)
        print("Game state: ", gameState)
    else:
        print("Number is too low")
        userAttempts += 1
        maxAttempts(userAttempts, gameState)

        #debugging
        print("Attempts: ", userAttempts)
        print("Game state: ", gameState)

print("\nGame finished.\n")

Answer 1

因为方法返回state的值，所以需要将这个新值赋给变量。将两个相关行更改为：

gameState = maxAttempts(userAttempts, gameState)

编辑： 在检查其他答案后，我意识到您的函数定义缺少以下内容：

else:
    return True