我是python的新手,我只是在创建一个简单的随机数猜测游戏
简单地说,要跳出while循环,用户必须猜测正确的数字或达到最大尝试次数,即3次
但是,当我调用函数检查尝试次数时,代码似乎没有中断循环。有没有办法从调用函数的while循环中解脱出来
import random
print("*** RANDOM NUMBER GUESSING ***\n")
print("1. Guess the number between x and y.")
print("2. You have 3 attempts to guess the random number.\n")
x = input("The random number is generated between x: ")
x = int(x)
y = input ("and y: ")
y = int(y)
#Random number generated
randNum = random.randint(x,y)
userAttempts = 0
gameState = True
#Function checking the attempts made
#If max attempts reached then gameState = False to break out of the while loop
def maxAttempts(attempts, state):
if attempts == 3:
print("Max attempts reached!")
state = False
return state
while gameState:
userNum = input("Guess the random: ")
userNum = int(userNum)
if userNum == randNum:
print("Well done you guessed the correct number !!")
gameState = False;
elif userNum > randNum:
print("Number is too high")
userAttempts += 1
maxAttempts(userAttempts, gameState)
#debugging
print("Attempts: ", userAttempts)
print("Game state: ", gameState)
else:
print("Number is too low")
userAttempts += 1
maxAttempts(userAttempts, gameState)
#debugging
print("Attempts: ", userAttempts)
print("Game state: ", gameState)
print("\nGame finished.\n")
在
maxAttempts
中更新state
时,只需更改局部变量state
的值您希望返回更新后的值并按照更实用、更纯的函数方法重新分配它:
您正在maxAttempts函数中设置
state = False
。 我想你是在假设这会自动生成gameState = False
。 这是不正确的。 您必须将函数调用为:gameState = maxAttempts(userAttempts, gameState)
因为方法返回state的值,所以需要将这个新值赋给变量。将两个相关行更改为:
编辑: 在检查其他答案后,我意识到您的函数定义缺少以下内容:
相关问题 更多 >
编程相关推荐