在单元格中写入带分隔符的CSV文件（两点）

Question

如何将以下内容写入.csv文件：

1171837, 1974:3655:1862:279:1936
1172, 238:1833:228:234:1821:225:211:245:1941:315:2035:222:3371:231:224:216:1942

而不是这样：

1171837, ['1974', '3655', '1862', '279', '1936']
1172, ['238', '1833', '228', '234', '1821', '225', '211', '245', '1941', '315', '2035', '222', '3371', '231', '224', '216', '1942']

以下是我的清单：

lche=['1171837', '1172']
ltarg=[['1974', '3655', '1862', '279', '1936'],
       ['238', '1833', '228', '234', '1821', '225', '211', '245', '1941',
        '315', '2035', '222', '3371', '231', '224', '216', '1942']]

我就是这样做的。我不知道如何使用其他分隔符。你知道吗

data="list.csv"
csv_out = open(data, 'wb')
mywriter = csv.writer(csv_out)
for row in zip(lche,ltarg):
    mywriter.writerow(row)
csv_out.close()

Answer 1

可以将join的元素与冒号一起ltarg：

>>> ltarg2 = list()
>>> for elem in ltarg:
...     ltarg2.append(':'.join(elem))
...     
>>> ltarg2
['1974:3655:1862:279:1936', '238:1833:228:234:1821:225:211:245:1941:315:2035:222:3371:231:224:216:1942']

然后继续使用新列表：

for row in zip(lche,ltarg2):