<p>我有这样一根线：</p>
<pre><code> old_ActNacd_2016-12-21_07-09-08.txt:100:2016-12-21 07:08:20 - [HSM ]Handle Identity Request. Send Identity Response. timeout: 1550s
old_ActNacd_2016-12-21_08-21-04.txt:52:2016-12-21 07:21:42 - [HSM ]Handle Identity Request. Send Identity Response. timeout: 1550s
old_ActNacd_2016-12-21_08-37-50.txt:49:2016-12-21 08:23:34 - [HSM ]Handle Identity Request. Send Identity Response. timeout: 1550s
old_ActNacd_2016-12-21_15-00-47.txt:49:2016-12-21 08:39:16 - [HSM ]Handle Identity Request. Send Identity Response. timeout: 1550s
</code></pre>
<p>我试着这样做：</p>
<pre><code> #creating list after taking the string out
log_list = ostring.split('Handle Identity Request. Send Identity Response. timeout: 1550s')
for itr in log_list:
#getting the dates from the log_list
match = re.search(r'\d{4}-\d{2}-\d{2}', itr)
if match:
date = datetime.strptime(match.group(), '%Y-%m-%d').date()
</code></pre>
<p>这个过程工作得很好，但我只想在一个操作中完成，而不是在两个步骤中完成（拆分和匹配）</p>
<pre><code> Note:-I want to create a list of dates from the string present between ":" and "space" in the string. I don't want the date present with "_ActNacd_" string.
</code></pre>
<p>因此，我将创建一个包含日期的列表：</p>
<pre><code>['2016-12-21','2016-12-21', '2016-12-21', '2016-12-21']
</code></pre>
