我有以下函数,它返回一系列与州相关的县
def answer():
census_df.set_index(['STNAME', 'CTYNAME'])
for name, state, cname in zip(census_df['STNAME'], census_df['STATE'], census_df['CTYNAME']):
print(name, state, cname)
Alabama 1 Tallapoosa County
Alabama 1 Tuscaloosa County
Alabama 1 Walker County
Alabama 1 Washington County
Alabama 1 Wilcox County
Alabama 1 Winston County
Alaska 2 Alaska
Alaska 2 Aleutians East Borough
Alaska 2 Aleutians West Census Area
Alaska 2 Anchorage Municipality
Alaska 2 Bethel Census Area
Alaska 2 Bristol Bay Borough
Alaska 2 Denali Borough
Alaska 2 Dillingham Census Area
Alaska 2 Fairbanks North Star Borough
我想知道哪个州的县最多。我可以这样迭代每个状态:
counter = 0
counter2 = 0
for name, state, cname in zip(census_df['STNAME'], census_df['STATE'], census_df['CTYNAME']):
if state == 1:
counter += 1
print(counter)
if state == 1:
counter2 += 1
print(counter2)
等等。我可以确定状态的数量(rng = range(1, 56)
)并遍历它,但是创建56个列表是一场噩梦。有没有更简单的方法?你知道吗
Pandas允许我们在没有循环/迭代的情况下执行此类操作:
或者
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