我正在使用python 2.7
,我有一个包含列表的列表。你知道吗
以下是我的清单:
range_list=[['encoding_txt\\pirkagia_10b_192x144_15_qp_26_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 26, 35.1782, 136.8125, 300.788, 0.844, -3.5, '192x144'],
['encoding_txt\\pirkagia_10b_192x144_25_qp_26_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 26, 35.1782, 228.0208, 302.251, 0.962, -2.5, '192x144'],
['encoding_txt\\pirkagia_10b_384x288_15_qp_28_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 28, 35.2193, 275.4614, 1065.412, 2.167, -2, '384x288'],
['encoding_txt\\pirkagia_10b_384x288_25_qp_28_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 28, 35.2193, 459.1024, 1064.403, 2.771, -1, '384x288'],
['encoding_txt\\pirkagia_10b_720x576_15_qp_30_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 30, 35.5282, 484.3387, 3536.937, 6.679, 1.5, '720x576'],
['encoding_txt\\pirkagia_10b_720x576_25_qp_30_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 30, 35.5282, 807.2312, 3553.744, 6.637, 2.5, '720x576']]
我只想在第一行保留包含字符串_25_
的列表。你知道吗
例如,新列表必须是:
range_list1 = [['encoding_txt\\pirkagia_10b_192x144_25_qp_26_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 26, 35.1782, 228.0208, 302.251, 0.962, -2.5, '192x144'],
['encoding_txt\\pirkagia_10b_384x288_25_qp_28_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 28, 35.2193, 459.1024, 1064.403, 2.771, -1, '384x288'],
['encoding_txt\\pirkagia_10b_720x576_25_qp_30_ON_encoder_randomaccess_B16_Filters_ON_scalable_JOURNAL2017.txt', 30, 35.5282, 807.2312, 3553.744, 6.637, 2.5, '720x576']]
使用简单循环:
列表理解:
列表理解
new_list=[i for i in range_1]
与:使用生成器表达式:
输出
您可以使用一个简单的列表:
由于
range
是一个函数,我还更改了列表的名称。你知道吗相关问题 更多 >
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