我试图访问一个类的实例(称为“a”),该实例被传递给第二个类(称为“b”)。我的意图是通过修饰实例b的类来访问实例a,这样我就可以在实例a上设置一些后台线程任务,同时仍然使用实例b来执行其他更重要的任务。这可能吗?你知道吗
import threading
import inspect
Class doStuff():
def __init__(self, somePropertyFromAnotherClass):
self.lock = threading.Lock()
self.prop = somePropertyFromAnotherClass
def doCoolThreadingStuff():
print("do threading stuff with {}".format(self.prop))
def someDecorator(cls):
def wrapper(cls):
print(inspect.getrgspec(cls.__init__))
#ds = doStuff() ## this is the bit that i can't figure out!
wrapper(cls)
return cls
Class A():
def __init__(self):
self.obj = "i'm an object"
@someDecorator
Class B():
def __init__(self, obj):
self.obj = obj
def doSomethingWithObj():
print('doing something with obj')
if __name__ == "__main__":
a = A()
b = B(a)
这个装潢师体格不好
我能够使用上面的decorator定义访问类a的实例(传递给类B)
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