如何让变量在数组中搜索，并检查数字是否匹配

Question

def comparing_numbers(number1,number2,number3,number4,number5, numbers(), correct_numbers):
    if number1 == numbers():
        correct_numbers = correct_numbers + 1
print("")
if number2 == numbers():
    correct_numbers = correct_numbers + 1
print("")
if number3 == numbers():
    correct_numbers = correct_numbers + 1
print("")
if number4 == numbers():
    correct_numbers = correct_numbers + 1
print("")
if number5 == numbers():
    correct_numbers = correct_numbers + 1

comparing_numbers(number1,number2,number3,number4,number5, numbers(), correct_numbers)

print(correct_numbers)

所以基本上我需要一点代码，让我的五个变量（number1，number2，number3，number4，number5，）在一个名为（numbers（））的数组中搜索，如果变量中的数字与数组中的任何数字匹配，它会向我的变量添加一个（正确的数字）。我需要它搜索五次（每个变量）

我试着编一些代码来解释我说的话，但这行不通

谢谢

Answer 1

也许这就是你想做的

def comparing_numbers(number1,number2,number3,number4,number5, numbers):
  correct_numbers = 0
  for number in [number1,number2,number3,number4,number5]:
    if number in numbers:
      correct_numbers += 1  
  return correct_numbers

correct_numbers = comparing_numbers(number1,number2,number3,number4,number5, numbers)

print(correct_numbers)

Answer 2

你能把你的号码储存成一张单子吗？ 如果是：

numbersToCheck = [number1,number2,number3,number4,number5]
numbers = [1,2,3,4,5]

correct_numbers = len([num for num in numbers if num in numbersToCheck])

Answer 3

您正在复制函数中的代码，该函数可能属于for循环。看看我们如何简化函数，并迭代您的数字列表：

def comparing_numbers(check_numbers, numbers(), correct_numbers):
    for number in check_numbers:
        if number in numbers():
            correct_numbers += 1
    return correct_numbers

check_numbers = [number1, number2, number3, number4, number5]
correct_numbers = 0
print(comparing_numbers(check_numbers, numbers(), correct_numbers)