如果键和值与其他di不匹配，则从dict列表中删除dict

Question

我有一个字典列表，我想用其他字典的值来过滤它。你知道吗

orig_list = [{"name":"Peter","last_name":"Wick","mail":"Peter@mail.com","number":"111"},
{"name":"John","last_name":"Hen","mail":"John@mail.com","number":"222"},
{"name":"Jack","last_name":"Malm","mail":"Jack@mail.com","number":"542"},
{"name":"Anna","last_name":"Hedge","mail":"Anna@mail.com"},
{"name":"Peter","last_name":"Roesner","mail":"Peter2@mail.com","number":"445"},
{"name":"Tino","last_name":"Tes","mail":"Tino@mail.com","number":"985"},]

预期结果示例1：

filter = {"name":"Peter"}

orig_list[{"name":"Peter","last_name":"Wick","mail":"Peter@mail.com","number":"111"},
{"name":"Peter","last_name":"Roesner","mail":"Peter2@mail.com","number":"445"}]

预期结果示例2：

filter = {"name":"Peter","number":"445"}

orig_list[
{"name":"Peter","last_name":"Roesner","mail":"Peter2@mail.com","number":"445"}]

过滤器可以有多个键。可能的键有（姓名、姓氏、号码）。 基本上，我想要的是遍历dict列表，检查每个dict是否包含给定过滤器中的键，如果包含，检查键值是否匹配。如果他们没有，从dict列表中删除整个dict

最终列表不必是原始列表。它可以是一个新的列表。所以从原始列表中删除dicts不是强制性的。这些dict也可以复制到新的dict列表中。你知道吗

Answer 1

您可以使用列表理解：

orig_list = [{"name":"Peter","last_name":"Wick","mail":"Peter@mail.com","number":"111"},
{"name":"John","last_name":"Hen","mail":"John@mail.com","number":"222"},
{"name":"Jack","last_name":"Malm","mail":"Jack@mail.com","number":"542"},
{"name":"Anna","last_name":"Hedge","mail":"Anna@mail.com"},
{"name":"Peter","last_name":"Roesner","mail":"Peter2@mail.com","number":"445"},
{"name":"Tino","last_name":"Tes","mail":"Tino@mail.com","number":"985"},]

filter_by = {"name":"Peter"}


result = [dic for dic in orig_list if all(key in dic and dic[key] == val for key, val in filter_by.items())]
print(result)

输出：

[
  {
    "name": "Peter",
    "last_name": "Wick",
    "mail": "Peter@mail.com",
    "number": "111"
  },
  {
    "name": "Peter",
    "last_name": "Roesner",
    "mail": "Peter2@mail.com",
    "number": "445"
  }
]

对于filter_by = {"name":"Peter","number":"445"}，您可以得到：

[
  {
    "name": "Peter",
    "last_name": "Roesner",
    "mail": "Peter2@mail.com",
    "number": "445"
  }
]