匹配字典中的键和值

Question

每个键都与值进行比较（可以说键和值之间有拼写检查）。如果只有两个单词不匹配，则打印该键

input={“their”：“thuor”，“diksha”，“dijmno”} 输出=[“他们的”]

def find_correct(words_dict):
    count=0
    final_list=[]
    for key,value in words_dict.items():
        for i in range(len(value)): # this may need adjusting for different length words
            if(value[i]!=key[i]):
                count+=1 
            if(count<=2):
                final_list.append(key)

    return final_list

print(find_correct({"their":"thuor","diksha":"dijmno"}))

Answer 1

这可以通过列表理解和集合来完成

print([i for i in d if len(set(i) - set(d[i])) == 2])