擅长:python、mysql、java
<p>我找到了解决办法-</p>
<pre><code>df_replace2 = df.replace(to_replace = r"(\r)(?![A-Z])", value = "", regex=True)
df_replace3 = df_replace2.replace(to_replace = r"(\r)(?![a-z])", value = " ", regex=True)
</code></pre>
<p>感谢@Brigadeiro指导解决方案</p>