我有航班代码的数据。 它有很多这样的字符串:
routing = 'PBI-FLL/FMY/JAX/MIA/ORL-PNS/TPA-SRQ-CLE/CHI/HOU/WAS-DEN-ELP'
我需要得到如下字符串的列表:
routinglist = [['PBI'], ['FLL','FMY','JAX','MIA','ORL'], ['PNS','TPA'], ['SRQ'], ['CLE','CHI','HOU','WAS'], ['DEN']]
我写了这个代码,但它是复杂的,不能按需要工作
routingrules = 'PBI-FLL/FMY/JAX/MIA/ORL-PNS/TPA-SRQ-CLE/CHI/HOU/WAS-DEN-ELP'
airports = []
nn = 0
few = ''
airportcount = 0
for simvol in routingrules:
if (nn) % 4 == 0:
previous = routingrules[nn:nn+3]
if routingrules[nn+3:nn+4] == '/':
few = few + previous + "1,2"
elif routingrules[nn+3:nn+4] == '-':
if few != '':
airports.append([few + previous])
airportcount = airportcount+1
few = ''
else:
airports.append([previous])
airportcount = airportcount+1
else:
if few != '':
airports.append([few + previous])
airportcount = airportcount+1
few = ''
nn = nn+1
nn = nn+1
print airports
它打印出来了
[['PBI'], ['FLL1,2FMY1,2JAX1,2MIA1,2ORL'], ['PNS1,2TPA'], ['SRQ'], ['CLE1,2CHI1,2HOU1,2WAS'], ['DEN']]
在
-
上拆分,然后在/
上拆分每个组:这将输出:
与您的示例相比,这是结尾处的一个额外的
['ELP']
条目,但我认为这是一个疏忽。很容易再把它去掉。你知道吗尽管对这个问题来说可能有点过分,^{} 在这里工作得很好。你知道吗
印刷品:
当你想扩展语法时,这里的优势就来了。通常这些问题一开始很简单,随着时间的推移变得越来越复杂,这里将语法与解析分离是很有用的。你知道吗
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