将导入模块中类的方法分配给当前namesp

Question

我想从导入模块中的类向当前名称空间分配方法（一次分配多个），我想不在“当前”名称空间中执行“分配过程”，而是从导入模块执行“分配过程”。我该怎么做？你知道吗

此文件是从另一个文件导入的：

# File mylib.py

class MyLib():
    def hello1(self, text):
        print('hello1: %s' % text)

    def goodbye1(self, text):
        print('goodbye1: %s' % text)

    def hello2(self, text):
        print('hello2: %s' % text)

    def goodbye2(self, text):
        print('goodbye2: %s' % text)

    def assign1(self):
        pass
        # This should assign self.hello1() and self.goodbye1()
        # to "parent" namespace as hello() and goodbye()

    def assign2(self):
        pass
        # Similar behaviour to self.assign1()

这个文件是“主”文件。你知道吗

# File myscript.py

import mylib

l = mylib.MyLib()
l.assign1()

# After this I would like to have MyLib.hello1() assigned to hello()
# and MyLib.goodbye1() to goodbye()

hello('hi')
goodbye('see you')

l.assign2()
# After this I would like to have MyLib.hello2() assigned to hello()
# and MyLib.goodbye2() to goodbye()

hello('hi')
goodbye('see you')

到目前为止，我尝试了globals()但没有成功，我发现__builtins__可能有用，但似乎不是正确的方法，因为__builtins__命名空间中有不属于它的内容。你知道吗

我不想要的是：

# In the "current" namespace
hello = l.hello1
goodbye = l.goodbye1

# Instead I want

l.assign1()
# Now hello() and goodbye() are mapped to l.hello1() and l.goodbye1()
# "automatically" - the assign process was done in l.assign1(),
# not here in the "current" namespace.

谢谢你的帮助。你知道吗

Answer 1

我认为最好是重新构造代码，这样就不必这样做，或许可以这样：

# File mylib.py

class MyLib():
    #...

    def assign1(self):
        return hello1, goodbye1

    #likewise for assign2

对于主剧本。。。你知道吗

# File myscript.py

import mylib

l = mylib.MyLib()
hello, goodbye = l.assign1()

---

如果真的想更改父命名空间中的内容，那么一种方法可能是：

# File mylib.py

class MyLib():
    def __init__(self, funcs): #funcs should be a list
        self.funcs = funcs

    #...

    def assign1(self):
        # This should assign self.hello1() and self.goodbye1()
        # to "parent" namespace as hello() and goodbye()

        self.funcs[0].__code__ = self.hello1.__code__
        self.funcs[1].__code__ = self.goodbye1.__code__

    #likewise for assign2

对于主剧本。。。你知道吗

# File myscript.py

import mylib

hello = lambda s:s
goodbye = lambda s:s

l = mylib.MyLib([hello, goodbye])
l.assign1()

然而，我想说的是，这给我的印象更像是……“肮脏”。就像，这不是很干净或者很像Python。对于未来/更大的项目，请使用第一种方法。你知道吗