我可以从我的请求函数中获取字典。我得到的是:
{
'collaborative': False,
'external_urls': {
'spotify': 'http://open.spotify.com/user/dashrif/playlist/3LEoetnegEv2Q8jdmB8TER'
},
'href': 'https://api.spotify.com/v1/users/dashrif/playlists/3LEoetnegEv2Q8jdmB8TER',
'id': '3LEoetnegEv2Q8jdmB8TER',
'images': [{
'height': 640,
'url': 'https://mosaic.scdn.co/640/0cd0508f78c5e5f6e2b01b3009753083c7977270527f35929eff151f80bcabec17b2fb9383da342b32d7d3432ff965abb01f706ec2efc38282a11b45d088e352f19eebb53874fcdc4366ff4249da45fe',
'width': 640
},
{
'height': 300,
'url': 'https://mosaic.scdn.co/300/0cd0508f78c5e5f6e2b01b3009753083c7977270527f35929eff151f80bcabec17b2fb9383da342b32d7d3432ff965abb01f706ec2efc38282a11b45d088e352f19eebb53874fcdc4366ff4249da45fe',
'width': 300
},
{
'height': 60,
'url': 'https://mosaic.scdn.co/60/0cd0508f78c5e5f6e2b01b3009753083c7977270527f35929eff151f80bcabec17b2fb9383da342b32d7d3432ff965abb01f706ec2efc38282a11b45d088e352f19eebb53874fcdc4366ff4249da45fe',
'width': 60
}],
'name': 'Life Playlist Vol. I: The Fuck You Getting Hype For? You Still Broke',
'owner': {
'external_urls': {
'spotify': 'http://open.spotify.com/user/dashrif'
},
'href': 'https://api.spotify.com/v1/users/dashrif',
'id': 'dashrif',
'type': 'user',
'uri': 'spotify:user:dashrif'
},
'public': True,
'snapshot_id': 'PCG8b/CxCfaCjX0mmFMZ3T9NUsJC1sz5MVAXfQf3aefQhcAi4Zdm2k+3rySb/HLw',
'tracks': {
'href': 'https://api.spotify.com/v1/users/dashrif/playlists/3LEoetnegEv2Q8jdmB8TER/tracks',
'total': 63
},
'type': 'playlist',
'uri': 'spotify:user:dashrif:playlist:3LEoetnegEv2Q8jdmB8TER'
}
至少我希望这是一本字典。老实说,在这一点上,我得到了这么多的错误,我不太确定。以下是相关代码:
playlist_api_endpoint = "{}/playlists".format(profile_data["href"])
playlists_response = requests.get(playlist_api_endpoint,
headers=authorization_header)
playlist_data = json.loads(playlists_response.text)
display_arr = [profile_data] + playlist_data["items"]
return render_template("index.html",sorted_array=display_arr)
基本上,我希望在添加新播放列表时能够过滤掉最后一个uri对象和任何其他uri对象。我尝试了.items()、筛选字典和其他一些我不记得的东西。如果有人知道我错在哪里或者如何实现我的目标,我希望得到一些帮助。谢谢!你知道吗
目前没有回答
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