美化输出到lis的组元素

Question

我有一个使用BeautifulSoup的输出。你知道吗

1. 我需要转换'type''bs4的输出。元素.标记“到一个列表，并将该列表导出到一个数据帧列，名为column\u a

2. 我希望输出停止在第14个元素（最后三个h2没有用）

我的代码：

import requests
from bs4 import BeautifulSoup


url = 'https://www.planetware.com/tourist-attractions-/oslo-n-osl-oslo.htm'
url_get = requests.get(url)
soup = BeautifulSoup(url_get.content, 'html.parser')
attraction_place=soup.find_all('h2', class_="sitename")    

for attraction in attraction_place:
    print(attraction.text)
    type(attraction)

输出：

1  Vigeland Sculpture Park
2  Akershus Fortress
3  Viking Ship Museum
4  The National Museum
5  Munch Museum
6  Royal Palace
7  The Museum of Cultural History
8  Fram Museum
9  Holmenkollen Ski Jump and Museum
10  Oslo Cathedral
11  City Hall (Rådhuset)
12  Aker Brygge
13  Natural History Museum & Botanical Gardens
14  Oslo Opera House and Annual Music Festivals
Where to Stay in Oslo for Sightseeing
Tips and Tours: How to Make the Most of Your Visit to Oslo
More Related Articles on PlanetWare.com

我希望有这样的清单：

attraction=[Vigeland Sculpture Park, Akershus Fortress, ......]

事先非常感谢。你知道吗

Answer 1

new = []
count = 1
for attraction in attraction_place:
    while count < 15:
        text = attraction.text
        new.append(text)
        count += 1

Answer 2

你可以用切片。你知道吗

for attraction in attraction_place[:14]:
    print(attraction.text)
    type(attraction)

Answer 3

一个很简单的方法是获取照片的alt属性。这样可以得到干净的文本输出，并且只有14个文本，而不需要切片/索引。你知道吗

from bs4 import BeautifulSoup
import requests

r = requests.get('https://www.planetware.com/tourist-attractions-/oslo-n-osl-oslo.htm')
soup = bs(r.content, 'lxml')
attractions = [item['alt'] for item in soup.select('.photo [alt]')]
print(attractions)