def randomSet (n, up):
"""Build a random 'set' of integers.
>>> randomSet(4, 10)
[5, 3, 2, 8]
Params:
n (int): # of integers in the set
up (int): upperbound
Returns: (list) random 'set' of n integers between 0 and up, inclusive
"""
A = []
for i in range(0,n):
randomInt = randrange(0, up)
def checkDuplicates (randomInt):
if randomInt not in A:
A.append(randomInt)
else:
randomInt = randrange(0,up)
checkDuplicates(randomInt)
checkDuplicates(randomInt)
return A
我读过几个答案,通常是有人按照a=a.append(randomInt)的思路做了一些事情,返回nonetype,但我不明白为什么是我的。 编辑:如果我尝试打印列表,它会。但是如果我输入(A),它将返回none,并且不允许我在另一个函数中迭代它。你知道吗
当我运行这段代码时,问题就出现了。你知道吗
def printSet (A):
"""Print a 'set', using standard set notation.
>>> printSet ([1,2,3,4])
{1, 2, 3, 4}
>>> printSet ([[1,2], [1,3]]
{{1, 2}, {1, 3}}
Params: A (list): set of integers, represented internally as a list
"""
newSet = set()
for a in range(len(A)):
if A[a] not in newSet:
newSet.add(A[a])
else:
printSet(A)
print(A, end='')
TypeError:类型为“NoneType”的对象没有len() ^指向:对于范围(len(a)):
目前没有回答
相关问题 更多 >
编程相关推荐