使用Python提取符合模式的子字符串，代码量较少

Question

我的python字符串结尾用换行符分隔：

mystring = "owner: uid=rocdsc,ou=People,dc=fcd,dc=test,dc=com
member: uid=absylor12,ou=people,dc=fcd,dc=test,dc=com
member: uid=amslsmith,ou=people,dc=fcd,dc=test,dc=com
member: uid=amis,ou=people,dc=fcd,dc=test,dc=com
member: uid=null,ou=people,dc=fcd,dc=test,dc=com""

有没有更好的方法来生成uid数组，只需如下所示：

[rocdsc, absylor12, amslsmith, amis]

没有

null

在数组列表中。你知道吗

我试过：

uids= [name.strip() for name in mystring .split("\n")]        

    if len(uids)>0:
        for index in range(len(uids))
            #print 'Current UIDs:', uids[index].split(":")
            uids[0] = uids[0].split("=")[1].strip()
    print uids

Answer 1

#!python2

import re

mystring = "owner: uid=rocdsc,ou=People,dc=fcd,dc=test,dc=com, member: uid=absylor12,ou=people,dc=fcd,dc=test,dc=com, member: uid=amslsmith,ou=people,dc=fcd,dc=test,dc=com, member: uid=amis,ou=people,dc=fcd,dc=test,dc=com, member:, uid=null,ou=people,dc=fcd,dc=test,dc=com"

# pattern definition
p = 'uid='

# holds user names
users = []

# split string on a space or a comma, find user id, append to list
for item in re.split(' |,|', mystring):
    if item.startswith(p):
        users.append(item.replace(p, ''))

print users