在比较lis中的项目时,我想将列表拆分为两个列表,即右\u顺序[]和反\u顺序[]

2024-10-03 11:19:56 发布

您现在位置:Python中文网/ 问答频道 /正文

我有一个result列表,它有两个有序项,比如A,B和B,一个组合,或者它可以是1,2和2,1等等,如果我们发现了A,B,1,2,3211,3222或任何东西的反向组合,那么反向组合应该存储在target_list,正确的有序组合应该存储在source_list。同样,如果我们没有找到任何反向组合,那么将其添加到source_list,但是target_list必须只包含source_list中项目的反向组合。你知道吗

这是我的代码,我得到的只是A,B的组合,你能告诉我如何动态地做,比如代替A,它可以是任何东西,代替B,它可以是任何应该满足上述条件的东西吗

result = [('A','B', 'IP1','GP1'), ('B', 'C', 'IP2','GP2'),('A', 'C', 'IP3','GP2'),('A','B', 'IP4','GP2'),('D', 'Z', 'IP5','GP2'),('B', 'A', 'IP6','GP2'), ('C','B','IP7','GP2'), ('C', 'A', 'IP8','GP2'),('C','B','IP9','GP2')]
a=[i for i,v in enumerate(result) if v[:2]==('B','A')]
Source_list,target_list=result[:a[0]],result[a[0]:]
print(Source_list)
print(target_list)

输出:

[('A', 'B', 'IP1', 'GP1'), ('B', 'C', 'IP2', 'GP2'), ('A', 'C', 'IP3', 'GP2'), ('A', 'B', 'IP4', 'GP2'), ('D', 'Z', 'IP5', 'GP2')]
[('B', 'A', 'IP6', 'GP2'), ('C', 'B', 'IP7', 'GP2'), ('C', 'A', 'IP8', 'GP2'), ('C', 'B', 'IP9', 'GP2')]


Tags: sourcetargetresultlist有序ip2ip4ip1
1条回答
网友
1楼 · 发布于 2024-10-03 11:19:56

我不太明白你在说什么,但你会告诉我。。。你知道吗

def kamoulox(results):
    source_list = []
    target_list = []
    combis = set((result[0], result[1]) for result in results if result[0] <= result[1])
    for combi in combis:
        i = 0
        while i < len(results):
            if results[i][0:2] == combi:
                source_list.append(results.pop(i))
            elif results[i][0:2] == combi[::-1]:
                target_list.append(results.pop(i))
            else:
                i += 1
    return source_list, target_list

results = [
    ('32891', '32822', 'EKRGMD92-vMME-01', '10.88.158.81'),
    ('32822', '32891', 'EKRGMD92-vMME-02', '10.88.159.113'),
    ('32822', '32891', 'HRSNNJAQ-vMME-01', '10.88.162.81'),
    ('32822', '32891', 'HRSNNJAQ-vMME-02', '10.88.163.113'),
    ('32822', '32781', 'EKRGMD92-vMME-02', '10.88.159.113'),
    ('32822', '32781', 'HRSNNJAQ-vMME-01', '10.88.162.81'),
    ('32822', '32781', 'HRSNNJAQ-vMME-02', '10.88.163.113'),
    ('33033', '32891', 'EKRGMD92-vMME-02', '10.88.159.113'),
    ('33033', '32891', 'HRSNNJAQ-vMME-01', '10.88.162.81'),
    ('33033', '32891', 'HRSNNJAQ-vMME-02', '10.88.163.113'),
    ('33033', '32822', 'EKRGMD92-vMME-01', '10.88.158.81'),
    ('33033', '32781', 'EKRGMD92-vMME-02', '10.88.159.113'),
    ('33033', '32781', 'HRSNNJAQ-vMME-01', '10.88.162.81'),
    ('33033', '32781', 'HRSNNJAQ-vMME-02', '10.88.163.113'),
    ('32781', '32891', 'KSCYMOEC-MME-03', '10.148.9.19'),
    ('32781', '32822', 'EKRGMD92-vMME-01', '10.88.158.81'),
    ('32781', '32822', 'KSCYMOEC-MME-03', '10.148.9.19'),
    ('32781', '33033', 'KSCYMOEC-MME-03', '10.148.9.19')
]
source_list, target_list = kamoulox(results)

# source_list contains good ordered items (with or without reversed equivalent)
# target_list contains wrong ordered items with at least one equivalent into source_list
# results now contains wrong ordered items without good ordered equivalent

相关问题 更多 >