擅长:python、mysql、java
<p>改用urllib2,这是一个非常酷的从网页抓取数据的库。你知道吗</p>
<pre><code>import urllib2
from lxml import html
url = "Sample url"
html_code = urllib2.urlopen(url)
parsed_source = html.fromstring(html_code) # This will give you html source as string, on which xpath can be applied.
link = parsed_source.xpath("//a/@href") # This code will return a list of href values on the html source, this Xpath is to be modified as per the html which is displayed in the UI.
</code></pre>
<p>这是一个示例代码,您应该如何处理这个问题,因为您必须编写自己的xpath来获取数据。你知道吗</p>