擅长:python、mysql、java
<p>我可不想在这儿坐一班车。简单的for循环是最好的:</p>
<pre><code>>>> for d,link in zip(sources, links):
... d['src'] = link
>>> print(sources)
[{'src': 'link1'}, {'src': 'link2'}, {'src': 'link3'}, {'src': 'link3'}, {'src': 'link4'}, {'src': 'link5'}, {'src': 'link6'}, {'src': 'link6'}, {'src': 'link7'}, {'src': 'link8'}]
</code></pre>