python线程如何运行其参数？

Question

我有一个python线程问题。我已经四处找了一天多了，情况没有好转，所以我想寻求帮助。我使用python3.4。 第一个问题是：

class myThread (threading.Thread):
    def __init__(self, url):
        threading.Thread.__init__(self)
        self.url = url
    def run(self):
        spider (url)

我在代码的某个部分使用了toBeProcessed +'/robots.txt'。如果我使用上述方法，它不会给我错误-但它仍然不能像它应该的那样工作，不是所有的线程都运行。如果我使用下面的方法，它会告诉我unsupported operand type(s) for +: '_thread._local' and 'str'：

def run(self):
    spider (self.url)

注意，我确实有这个声明toBeProcessed = threading.local()。你知道吗

第二个问题是关于代码的其余部分，只有两个线程完成了工作，其余的线程——不管它们的编号是多少都不起作用。你知道吗

完整代码：

def spider(url,superMaxPages):
    print(threading.current_thread())
    toBeProcessed = threading.local()
    data = threading.local()
    parser = threading.local()
    links = threading.local()
    lock = threading.Lock()
    writeLock = threading.Lock()

    # Start from the beginning of our collection of pages to visit:
    while 1:
        if LinkParser.numVisited > maxPages:
            print ('max pages reached')
            break

        lock.acquire()
        try:
            if not url:
                time.sleep(0.01)
                lock.release()
                continue
            print('to be processed ')
            toBeProcessed = url.pop()
        except:
            print('threading error')
        lock.release()
        # In case we are not allowed to read the page.
        rp = robotparser.RobotFileParser()
        rp.set_url(toBeProcessed +'/robots.txt')
        rp.read()
        if not(rp.can_fetch("*", toBeProcessed)):
            continue

        LinkParser.visited.append(toBeProcessed)

        LinkParser.numVisited += 1

        writeLock.acquire()
        try:
            f.write(toBeProcessed+'\n')
        finally:
            writeLock.release()

        try:
            parser = LinkParser()
            data, links = parser.getLinks(toBeProcessed)        
            # Add the pages that we visited to the end of our collection
            url = url + links
            print("One more page added from &i",threading.get_ident())
        except:
            print(" **Failed!**")

class myThread (threading.Thread):
    def __init__(self, url, maxPages):
        threading.Thread.__init__(self)
        self.maxPages = maxPages
        self.url = url
    def run(self):
        spider (self.url, maxPages)

不是像这样初始化url url = [] 这就是我运行线程的方式， myThread( spider, (url,maxPages) ).start

Answer 1

你做错了。不能用字符串连接^{}的实例。您需要在local实例上存储一个属性，如下所示：

import threading

toBeProcessed = threading.local()
toBeProcessed.url = url.pop()     
toBeProcessed.url += '/robots.txt'

此外，您应该考虑在__init__方法中使用^{}。你知道吗