擅长:python、mysql、java
<p>将其转过来;删除URL:</p>
<pre><code>re.sub(r'\bhttps?://[^# ]+#?', '', text1)
</code></pre>
<p>演示:</p>
<pre><code>>>> import re
>>> text1 = '\bhttp://oaei.ontologymatching.org/2011/benchmarks/101/onto.rdf#Reference http://oaei.ontologymatching.org/2011/benchmarks/101/onto.rdf#Informal ACADEMIC type http://oaei.ontologymatching.org/2011/benchmarks/101/onto.rdf#school ACADEMIC type'
>>> re.sub(r'https?://[^# ]+#?', '', text1)
'Reference Informal ACADEMIC type school ACADEMIC type'
</code></pre>
<p>表达式查找以<code>http://</code>或<code>https://</code>开头的任何内容,并删除其后不是哈希或空格的任何内容,包括可选哈希。你知道吗</p>