从csv读取列表，len只显示一项

Question

以下是csv文件中唯一的一行：

0.0028,0.008,0.0014,0.008,0.0014,0.008,0.0014,0.008,0.0014,0.008,0.0028,0.0

我想把它读入一个列表，然后数一数项目的数量。你知道吗

import csv
with open('StackupThick.csv', 'r') as infile:
    reader = csv.reader(infile, delimiter=',')
    mylist = list(reader)
    print(mylist)
    print(len(mylist))

但是，打印结果如下所示：

[['0.0028', '0.008', '0.0014', '0.008', '0.0014', '0.008', '0.0014', '0.008', '0.0014', '0.008', '0.0028', '0.0']]
1

困扰我的是双括号，len只返回一个。 它不应该只有一个括号而不是两个；len不应该返回12吗？你知道吗

Answer 1

你知道吗csv.reader文件返回一个允许在CSV的行上迭代的对象。您的文件有1行。如果要迭代行中的列，可以执行以下操作：

reader = csv.reader(infile, delimiter=',')
for row in reader:
    print(row)

Answer 2

您需要浏览文件的行：

import csv
with open('StackupThick.csv', 'r') as infile:
    reader = csv.reader(infile, delimiter=',')
    for row in reader:
        print(row)
        print(len(row))

它给出：

['0.0028', '0.008', '0.0014', '0.008', '0.0014', '0.008', '0.0014', '0.008', '0.0014', '0.008', '0.0028', '0.0']
12

看看here。你知道吗