从IPython控制台:
In [16]: b
Out[16]: datetime.datetime(2008, 3, 1, 0, 0)
In [17]: e
Out[17]: datetime.datetime(2010, 5, 2, 0, 0)
In [18]: rrule(MONTHLY).between(b, e, inc=True)
Out[18]:
[datetime.datetime(2009, 3, 6, 14, 42, 1),
datetime.datetime(2009, 4, 6, 14, 42, 1),
datetime.datetime(2009, 5, 6, 14, 42, 1),
datetime.datetime(2009, 6, 6, 14, 42, 1),
datetime.datetime(2009, 7, 6, 14, 42, 1),
datetime.datetime(2009, 8, 6, 14, 42, 1),
datetime.datetime(2009, 9, 6, 14, 42, 1),
datetime.datetime(2009, 10, 6, 14, 42, 1),
datetime.datetime(2009, 11, 6, 14, 42, 1),
datetime.datetime(2009, 12, 6, 14, 42, 1),
datetime.datetime(2010, 1, 6, 14, 42, 1),
datetime.datetime(2010, 2, 6, 14, 42, 1),
datetime.datetime(2010, 3, 6, 14, 42, 1),
datetime.datetime(2010, 4, 6, 14, 42, 1)]
如何使between()
返回日期从开始日期(b
)开始?
您需要将
b
传入rrule,如下所示:从这些文档(http://labix.org/python-dateutil)来看,调用rrule而不指定dtstart将使用datetime.datetime.now()作为稍后应用
between
的序列的起点。这就是为什么你的价值观始于2009-03-06。相关问题 更多 >
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