将num2text中的“十个一”改为十一的算法？

Question

我写了一个代码把数字翻译成文本：

num = raw_input("Insert a number > ")
numbers = {'0': '', '1': 'One ', '2': 'Two ', '3': 'Three ', '4': 'Four ',
           '5': 'Five ', '6': 'Six ', '7': 'Seven ', '8': 'Eight ', '9': 'Nine '}
tens = {'0': '', '1': 'Ten ', '2': 'Twenty ', '3': 'Thirty ', '4': 'Forty ',
        '5': 'Fifty ', '6': 'Sixty ', '7': 'Seventy ', '8': 'Eighty ', '9': 'Ninety '}
numbers_teens = {'0': '','1': 'Eleven ', '2': 'Twelve ', '3': 'Thirteen ',
                 '4': 'Fourteen ', '5': 'Fifteen ', '6': 'Sixteen ', '7': 'Seventeen ',
                 '8': 'Eighteen ', '9': 'Nineteen '}
numbers_teeens = {'0' : '', '1': 'One', '2': 'Two', '3': 'Three', '4': 'Four',
                  '5': 'Five', '6': 'Six', '7': 'Seven', '8': 'Eight', '9': 'Nine',
                  '11': 'Eleven', '12': 'Twelve', '13': 'Thirteen', '14': 'Fourteen',
                  '15': 'Fifteen', '16': 'Sixteen', '17': 'Seventeen', '18': 'Eighteen',
                  '19': 'Nineteen'}
numbers_hundreds = {}
numbers_thousands = {}
numbers_ten_thousands = {}
numbers_teen_thousands = {}
numbers_hundred_thousands = {}

#Creates dicts
for k,v in numbers.items():
    numbers_hundreds.update({k: v.title() + 'Hundred '})
if k == 0:
    numbers_hundreds.update({k: v.title() + ''})
if '0' in numbers_thousands:
    numbers_thousands.update({k: v.title() + ''})
numbers_thousands.update({k: v.title() + 'Thousand, '})

for k1,v1 in tens.items():
    numbers_ten_thousands.update({k1: v1.title()})

for kt,vt in numbers_teens.items():
    numbers_teen_thousands.update({kt: vt.title() + 'Thousand '})
if kt == 0:
    numbers_teen_thousands.update({kt: vt.title() + ''})

for k2,v2 in numbers_hundreds.items():
    numbers_hundred_thousands.update({k2: v2.title() + ''})

p = len(num)
i = p - 2
if p == 1:
    print numbers[num]
if p == 2:
    print tens[num[0]] + numbers_teeens[num[1]]

if p == 3:
    print numbers_hundreds[num[0]] + tens[num[1]] + numbers_teeens[num[2]]

if p == 4:
    print (numbers_thousands[num[0]] + numbers_hundreds[num[1]] + tens[num[2]]
           + numbers_teeens[num[3]])

if p == 5:
    print (numbers_ten_thousands[num[0]] + numbers_thousands[num[1]]
           + numbers_hundreds[num[2]] + tens[num[3]] + numbers_teeens[num[4]])

if p == 6:
    print (numbers_hundred_thousands[num[0]] + numbers_ten_thousands[num[1]]
           + numbers_thousands[num[2]]+ numbers_hundreds[num[3]] + tens[num[4]]
           + numbers_teeens[num[5]])

但是当我的输入是112时，我的输出是One Hundred Ten Two，（所有青少年都是如此，{11,12,13,14,15,16,17,18,19}）。应该是One Hundred Eleven，但我不知道怎么做。。。你知道吗

Answer 1

您可以通过以下步骤解决此问题：

1. 将数字键更改为11、12、14…等
2. 添加条件检查十位数，如果是1，则print numbers_teens[num[0]+num[1]]

我不明白你为什么需要另一个numbers_teeens（带3个e）

我应用了这些更改，请尝试以下代码：

numbers = {'0': '', '1': 'One ', '2': 'Two ', '3': 'Three ', '4': 'Four ',
           '5': 'Five ', '6': 'Six ', '7': 'Seven ', '8': 'Eight ', '9': 'Nine '}
tens = {'0': '', '1': 'Ten ', '2': 'Twenty ', '3': 'Thirty ', '4': 'Forty ',
        '5': 'Fifty ', '6': 'Sixty ', '7': 'Seventy ', '8': 'Eighty ', '9': 'Ninety '}
# 1- changed keys in numbers_teens:
numbers_teens = {'0': '','11': 'Eleven ', '12': 'Twelve ', '13': 'Thirteen ',
                 '14': 'Fourteen ', '15': 'Fifteen ', '16': 'Sixteen ', '17': 'Seventeen ',
                 '18': 'Eighteen ', '19': 'Nineteen '}
# removed number_teeens from here

#Creates dicts
for k,v in numbers.items():
    numbers_hundreds.update({k: v.title() + 'Hundred '})
    if k == 0:
        numbers_hundreds.update({k: v.title() + ''})
    if '0' in numbers_thousands:
        numbers_thousands.update({k: v.title() + ''})
    numbers_thousands.update({k: v.title() + 'Thousand, '})

for k1,v1 in tens.items():
    numbers_ten_thousands.update({k1: v1.title()})

for kt,vt in numbers_teens.items():
    numbers_teen_thousands.update({kt: vt.title() + 'Thousand '})
    if kt == 0:
        numbers_teen_thousands.update({kt: vt.title() + ''})

for k2,v2 in numbers_hundreds.items():
    numbers_hundred_thousands.update({k2: v2.title() + ''})

if p == 1:
    print numbers[num]
if p == 2:
    # 2- condition to check if tens digits == '1'
    if num[0] == '1':
        # print numbers_teens[the concatenation of the two digits]
        print numbers_teens[num[0]+num[1]]
    # if it is not == '1'
    else:
        print tens[num[0]] + numbers[num[1]]

if p == 3:
    # check if tens digits == '1'
    if num[1] == '1':
        print numbers_hundreds[num[0]] + numbers_teens[num[1]+num[2]]
    else:
        print numbers_hundreds[num[0]] + tens[num[1]] + numbers[num[2]]

if p == 4:
    # check if tens digits == '1'
    if num[2] == '1':
        print numbers_thousands[num[0]]+ numbers_hundreds[num[1]] + numbers_teens[num[2]+num[3]]
    else:
        print numbers_thousands[num[0]]+ numbers_hundreds[num[1]] + tens[num[2]] + numbers[num[3]]

if p == 5:
    # check if tens digits == '1'
    if num[3] == '1':
        print numbers_ten_thousands[num[0]] + numbers_thousands[num[1]]+ numbers_hundreds[num[2]] + numbers_teens[num[3]+num[4]]
    else:
        print numbers_ten_thousands[num[0]] + numbers_thousands[num[1]]+ numbers_hundreds[num[2]] + tens[num[3]] + numbers[num[4]]

if p == 6:
    # check if tens digits == '1'
    if num[4] == '1':
        print numbers_hundred_thousands[num[0]] + numbers_ten_thousands[num[1]] + numbers_thousands[num[2]]+ numbers_hundreds[num[3]] + numbers_teens[num[4]+num[5]]
    else:
        print numbers_hundred_thousands[num[0]] + numbers_ten_thousands[num[1]] + numbers_thousands[num[2]]+ numbers_hundreds[num[3]] + tens[num[4]] + numbers[num[5]]

现在当输入=112
输出为：One Hundred Twelve