擅长:python、mysql、java
<p>也许您可以定义两个返回True或False的检查函数:</p>
<pre><code>def jumpleft(x, y, board, incr):
return (board[x+incr][y+incr] != player) and (board[x+incr][y+incr] != '') and (board[x+(incr*2)][y+(incr*2)] == '') and 0 <= x <= 7 and 0 <= y <= 7 and 0 and 0 <= x+incr <= 7 and 0 <= x+(incr*2) <= 7 and 0 <= y+(incr*2) <= 7
def jumpright(x, y, board, incr):
return (board[x+incr][y-incr] != player) and (board[x+incr][y-incr] != '') and (board[x+(incr*2)][y-(incr*2)] == '') and 0 <= x <= 7 and 0 <= y <= 7 and 0 and 0 <= x+incr <= 7 and 0 <= x+(incr*2) <= 7 and 0 <= y-(incr*2) <= 7
</code></pre>
<p>打电话给他们就知道了。这将使您的代码更具可读性。你知道吗</p>