根据值从长列表中派生子列表

Question

我有下面的清单

list = [0,0,0,0,2,1,4,1,432,431,1,4,43,423,,45,54534,0,665,765,5687,89870,890,98089,6,0,1,5,7,3,6,7,8,3,4,4,7,543,6554,765,768,87234,765876,0,897,987,0,4,7,4,6,8,0,0,0,0]

从上面的列表中，我想根据高密度（>；10）值提取子列表。 如果在较高的数之间有一个或两个零，它可以包含在较高的数集中

我想打印

op1 = [2,1,4,1,432,431,1,4,43,423,,45,54534,0,665,765,5687,89870,890,98089,6,0]
op2 = [7,543,6554,765,768,87234,765876,0,897,987,0,4,7,4,6,8]

我想从上面的列表中提取更多的数字集。。你知道吗

高\u数字>；10 低数字<；10

main_list= [<few_high_numbers_1>,<few_low_numbers_1>,<few_high_numbers_2><few_low_numbers_2><few_high_n‌​umbers_3><few_low_numbers_3>]..

我想从中提取列表

list1 = <few_high_no_1> 
list2= <few_high_no_2> 
list3 = <few_high_no_3>

等等等等

如果我不清楚就告诉我。你知道吗

谢谢你

Answer 1

lists = []
low = True
for n in main_list:
    if n > 10:
        if not low:
            lists[-1].append(n)
        else:
            lists.append([n])
            low = False
    else:
        low = True