安卓gson。JsonSyntaxException:java。lang.illegalstate例外:
我是刚接触gson的人,所以犯了这个错误
com。谷歌。格森。JsonSyntaxException:java。lang.IllegalStateException:应为BEGIN_对象,但在第1行第2527列path$处为BEGIN_数组。数据击球[0]。分数[1]。解雇
这是因为API给出了不同的json回复
以下是json回复:
"batting": [
{
"scores": [
{
"dismissal-by": {
"name": "CE Rudd",
"pid": "646213"
},
"dismissal": "stumped",
"SR": 126,
"6s": 0,
"4s": 5,
"B": 34,
"R": 43,
"dismissal-info": "st Rudd b Kerr",
"batsman": "NE Bolton",
"pid": "267611"
},
{
"dismissal-by": [
{
"name": "M du Preez",
"pid": "54646"
}
],
"dismissal": "runout",
"SR": 112,
"6s": 0,
"4s": 4,
"B": 25,
"R": 28,
"dismissal-info": "run out (du Preez)",
"batsman": "GEB Boyce",
"pid": "874261"
},
{
"dismissal-by": {
"name": "LK Bell",
"pid": "878025"
},
"dismissal": "catch",
"SR": 100,
"6s": 0,
"4s": 2,
"B": 27,
"R": 27,
"dismissal-info": "c Bell b Scholfield",
"batsman": "AE Satterthwaite",
"pid": "233007"
},
{
"dismissal": "not out",
"SR": 220,
"6s": 2,
"4s": 5,
"B": 20,
"R": 44,
"dismissal-info": "not out",
"batsman": "H Kaur",
"pid": "372317"
},
{
"dismissal": "not out",
"SR": 100,
"6s": 0,
"4s": 1,
"B": 14,
"R": 14,
"dismissal-info": "not out",
"batsman": "E Threlkeld ",
"pid": "878035"
},
{
"SR": "",
"6s": "",
"4s": "",
"B": "",
"R": "",
"dismissal-info": "",
"detail": "6 (b 1, w 5)",
"batsman": "Extras",
"pid": 0
}
],
"title": "Lancashire Thunder Innings"
},
按对象获取第二次解雇时的错误
第一次按对象删除是从一个对象开始的,第二次按对象删除是从一个数组开始的
这是分数数组的java类
public class Score__ implements Serializable {
@SerializedName("dismissal-by")
@Expose
private DismissalBy dismissalBy;
@SerializedName("dismissal")
@Expose
private String dismissal;
@SerializedName("SR")
@Expose
private String sR;
@SerializedName("6s")
@Expose
private String _6s;
@SerializedName("4s")
@Expose
private String _4s;
@SerializedName("B")
@Expose
private String b;
@SerializedName("R")
@Expose
private String r;
@SerializedName("dismissal-info")
@Expose
private String dismissalInfo;
@SerializedName("batsman")
@Expose
private String batsman;
@SerializedName("pid")
@Expose
private Integer pid;
@SerializedName("detail")
@Expose
private String detail;
public DismissalBy getDismissalBy() {
return dismissalBy;
}
public void setDismissalBy(DismissalBy dismissalBy) {
this.dismissalBy = dismissalBy;
}
public String getDismissal() {
return dismissal;
}
public void setDismissal(String dismissal) {
this.dismissal = dismissal;
}
public String getSR() {
return sR;
}
public void setSR(String sR) {
this.sR = sR;
}
public String get6s() {
return _6s;
}
public void set6s(String _6s) {
this._6s = _6s;
}
public String get4s() {
return _4s;
}
public void set4s(String _4s) {
this._4s = _4s;
}
public String getB() {
return b;
}
public void setB(String b) {
this.b = b;
}
public String getR() {
return r;
}
public void setR(String r) {
this.r = r;
}
public String getDismissalInfo() {
return dismissalInfo;
}
public void setDismissalInfo(String dismissalInfo) {
this.dismissalInfo = dismissalInfo;
}
public String getBatsman() {
return batsman;
}
public void setBatsman(String batsman) {
this.batsman = batsman;
}
public Integer getPid() {
return pid;
}
public void setPid(Integer pid) {
this.pid = pid;
}
public String getDetail() {
return detail;
}
public void setDetail(String detail) {
this.detail = detail;
}
}
java类的解雇
public class DismissalBy implements Serializable {
@SerializedName("name")
@Expose
private String name;
@SerializedName("pid")
@Expose
private String pid;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getPid() {
return pid;
}
public void setPid(String pid) {
this.pid = pid;
}
}
如何解决这个问题? 任何帮助都将不胜感激
# 1 楼答案
在JSON对象中,有一个
你不能这样使用它,因为你把它声明为一个数组,它应该保持相同的类型,因为你需要把它改成
,
要解决这个问题,需要手动解析所有JSON,就像
# 2 楼答案
在数组格式中(以[和]开头,以]结尾),而在Json对象{}中,最好从API开发者那里解决它。或者,您可以将其声明为字符串,并在以后需要时进行解析
# 3 楼答案
那个JSON是无效的。。。因此
com.google.gson.JsonSyntaxException
它需要从一个
{
开始,在"title": "Lancashire Thunder Innings"
之后,有一个}]
缺失在那里你可以自己检查:https://jsonlint.com