在python中从单词包中搜索文本

Question

假设我有一包关键词。 例如：

['profit low', 'loss increased', 'profit lowered']

我有一个pdf文档，我从中解析整个文本， 现在我想得到与这袋单词相匹配的句子。你知道吗

假设一句话是：

'The profit in the month of November lowered from 5% to 3%.'

这应该匹配，因为在单词包中'profit lowered'匹配这个句子。你知道吗

用python解决这个问题的最佳方法是什么？你知道吗

Answer 1

# input
checking_words = ['profit low', 'loss increased', 'profit lowered']
checking_string = 'The profit in the month of November lowered from 5% to 3%.'

trans_check_words = checking_string.split()
# output
for word_bug in [st.split() for st in checking_words]:
    if word_bug[0] in trans_check_words and word_bug[1] in trans_check_words:
        print(word_bug)

Answer 2

您可以尝试以下操作：

将一袋单词转换成一个句子：

bag_of_words = ['profit low', 'loss increased', 'profit lowered']    
bag_of_word_sent =  ' '.join(bag_of_words)

然后是句子列表：

list_sents = ['The profit in the month of November lowered from 5% to 3%.']

使用Levenshtein距离：

import distance
for sent in list_sents:
    dist = distance.levenshtein(bag_of_word_sent, sent)
    if dist > len(bag_of_word_sent):
        # do something
        print(dist)

Answer 3

如果你的检查单词列表元素在长句中，你需要检查它

sentence = 'The profit in the month of November lowered from 5% to 3%.'

words = ['profit','month','5%']

for element in words:
    if element in sentence:
        #do something with it
        print(element)

如果您想更清楚，可以使用此单行循环将匹配的单词收集到列表中：

sentence = 'The profit in the month of November lowered from 5% to 3%.'

words = ['profit','month','5%']

matched_words = [] # Will collect the matched words in the next life loop:

[matched_words.append(word) for word in words if word in sentence]

print(matched_words)

如果列表中的每个元素上都有“间隔”单词，则需要使用split（）方法来处理它。你知道吗

sentence = 'The profit in the month of November lowered from 5% to 3%.'

words = ['profit low','month high','5% 3%']

single_words = []
for w in words:
    for s in range(len(w.split(' '))):
        single_words.append(w.split(' ')[s])

matched_words = [] # Will collect the matched words in the next life loop:
[matched_words.append(word) for word in single_words if word in sentence]

print(matched_words)