擅长:python、mysql、java
<p>循环解决方案:</p>
<pre><code>array1 = [6, 7, 8]
array2 = [1, 2, 3, 4, 5]
arr = []
for i in array1:
tmp = []
for j in array2:
tmp.append(i - j)
arr.append(tmp)
print(arr)
</code></pre>
<p>输出:</p>
<blockquote>
<p>[[5, 4, 3, 2, 1], [6, 5, 4, 3, 2], [7, 6, 5, 4, 3]]</p>
</blockquote>