擅长:python、mysql、java
<p>您可以使用如下<code>for</code>循环实现所需的输出:</p>
<pre><code>Names = ["London", "Tokyo", "Amsterdam", "Helsinki","New York","California"]
Odds = [2/1, 5/1, 4/1, 3/1, 7/1, 10/1]
start_nmb = 1
for nmb, odd in enumerate(Odds):
Names.insert(start_nmb, odd)
start_nmb += 2
</code></pre>
<p>输出:</p>
<pre><code>['London', 2.0, 'Tokyo', 5.0, 'Amsterdam', 4.0, 'Helsinki', 3.0, 'New York', 7.0, 'California', 10.0]
</code></pre>
<p>希望这有帮助!你知道吗</p>