擅长:python、mysql、java
<p>我的方法是:</p>
<pre><code>list = ['50003252714', 'Malle Kask',
'40003252714', 'Endel Kask',
'30003252714', 'Peeter Kask',
'60003252714', 'JĆ¼ri MƤnd',
'70003252714', 'Laura MƤnd',
'80003252714', 'Kerli MƤnd',
'10003252714', 'Elvo Pikk',
'20003252714', 'Signar Pikk']
</code></pre>
<p>使用<strong>iter()</strong>转换列表,然后在循环中使用<strong>next()</strong>迭代器:</p>
<pre><code>it = iter(a)
final = []
for a in it:
list_of_two = [a, next(it)]
final.append(list_of_two)
print(final)
</code></pre>
<p><strong>输出:</strong></p>
<pre><code>[['50003252714', 'Malle Kask'], ['40003252714', 'Endel Kask'], ['30003252714', 'Peeter Kask'], ['60003252714', 'JĆ¼ri MƤnd'], ['70003252714', 'Laura MƤnd'], ['80003252714', 'Kerli MƤnd'], ['10003252714', 'Elvo Pikk'], ['20003252714', 'Signar Pikk']]
</code></pre>