所以我有这样一句话:
{
"environment": [
{
"appliances": [
{
"services-status": "GOOD",
"ping-status": "REACHABLE"
},
{
"softwareVersion": "16.1-R1-S2 50b46b5 20170829",
"services-status": "GOOD",
"ping-status": "REACHABLE"
}
],
"vd_url": "https://bla1"
},
{
"appliances": [
{
"ipAddress": "10.4.64.108"
"type": "branch",
"sync-status": "IN_SYNC"
},
{
"services-status": "GOOD",
"ping-status": "REACHABLE"
"sync-status": "IN_SYNC"
}
],
"vd_url": "https://bla2"
},
],
"failed_urls": [
"https://gslburl",
"https://gslburl",
"https://localhost",
"https://localhost",
"https://localhost"
]
}
也可以是这样的
{
"softwareVersion": "16.1-R1-S2 50b46b5 20170829",
"services-status": "GOOD",
"ping-status": "REACHABLE"
"vd_url" : "https://blah3"
}
也可以是这样的
{
"environment": [
{
"appliances": [
{
"services-status": "GOOD",
"ping-status": "REACHABLE"
},
{
"softwareVersion": "16.1-R1-S2 50b46b5 20170829",
"services-status": "GOOD",
"ping-status": "REACHABLE"
}
],
"vd_url": "https://bla1"
}
]
}
也可以是任何可能的字典组合,但我想实现的是编写一个通用函数,可以接受字典, 用另一个值替换一个键并返回新的dict。 只是一个伪代码:
def replace(dict_obj, key, new_value)
for dict in dict_obj:
for k, v in dict.items()
if k == key:
dict[k] = new_value
return dict_obj
但最终我想要的是与我传递的dictionary对象相同的dict\u obj,但是带有新的值,它应该适用于上面任何类型的dict 我绞尽脑汁想怎么解决这个问题:(
您可以使用递归来确定键、值对中的值是列表还是dict,然后进行相应的迭代。你知道吗
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