擅长:python、mysql、java
<p>最简单的基于循环的解决方案是:</p>
<pre><code>result = ""
for i in answer:
if result == "" or result[-1] != i:
result += i
</code></pre>
<p>您还可以使用<a href="https://docs.python.org/2/library/itertools.html#itertools.groupby" rel="nofollow noreferrer">^{<cd1>}</a>,它完成您要查找的内容:</p>
<pre><code>print("".join([i for i in map(lambda x: x[0], itertools.groupby(answer))])
</code></pre>