我试着为视频游戏Pong编写一个策略梯度算法。 代码如下:
import tensorflow as tf
import gym
import numpy as np
import matplotlib.pyplot as plt
from os import getcwd
num_episodes = 1000
learning_rate = 0.01
rewards = []
env_name = 'Pong-v0'
env = gym.make(env_name)
x = tf.placeholder(tf.float32,(None,)+env.observation_space.shape)
y = tf.placeholder(tf.float32,(None,env.action_space.n))
def net(x):
layer1 = tf.layers.flatten(x)
layer2 = tf.layers.dense(layer1,200,activation=tf.nn.softmax)
layer3 = tf.layers.dense(layer2,env.action_space.n,activation=tf.nn.softmax)
return layer3
logits = net(x)
loss = tf.losses.sigmoid_cross_entropy(y,logits)
train = tf.train.GradientDescentOptimizer(learning_rate).minimize(loss)
saver = tf.train.Saver()
init = tf.global_variables_initializer()
sess = tf.Session()
with tf.device('/device:GPU:0'):
sess.run(init)
for episode in range(num_episodes):
print('episode:',episode+1)
total_reward = 0
losses = []
training_data = []
observation = env.reset()
while True:
if max(0.1, (episode+1)/num_episodes) > np.random.uniform():
probs = sess.run(logits,feed_dict={x:[observation]})[0]
action = np.argmax(probs)
else:
action = env.action_space.sample()
onehot = np.zeros(env.action_space.n)
onehot[action] = 1
training_data.append([observation,onehot])
observation, reward, done, _ = env.step(action)
total_reward += reward
if done:
break
if total_reward >= 0:
learning_rate = 0.01
else:
learning_rate = -0.01
for sample in training_data:
l,_ = sess.run([loss,train],feed_dict={x:[sample[0]], y:[sample[1]]})
losses.append(l)
print('loss:',l)
print('average loss:',sum(losses)/len(losses))
saver.save(sess,getcwd()+'/model.ckpt')
rewards.append(total_reward)
plt.plot(range(episode+1),rewards)
plt.ylabel('total reward')
plt.xlabel('episodes')
plt.savefig(getcwd()+'/reward_plot.png')
但在我训练了我的网络之后,剧本的情节似乎表明网络在接近尾声时变得更糟了。同样在上一集中,所有训练示例的损失都是一样的(~0.68),当我尝试测试网络时,球员的球拍只是静止不动。有什么方法可以改进我的代码吗?你知道吗
我想请你熟悉如何使用张量流编码神经网络,因为问题就在这里。您在两个nn层中都提供了
activation=tf.nn.softmax
,这两个nn层应该是一个终端层(因为您试图找到最大的动作概率)。您可以在第二层中将其更改为tf.nn.relu
。learning_rate
有一个更大的问题:Negative learning rate makes absolutely no sense。您希望学习率为正(现在可以使用常数0.01)。你知道吗
另外,还有一个注释,您没有提到
observation_space
形状,但我假设它是一个2D矩阵。然后可以在将其输入x
之前对其进行整形。所以您不需要不必要地使用tf.flatten
。你知道吗相关问题 更多 >
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