按子串分组

Question

select substr(word,1,1) as alpha, count(*) as count
from words
group by substr(word,1,1);

我想在PonyORM中实现这个，有人能帮我写查询语句吗？提前谢谢

Answer 1

其实很简单

query = select(
    (w.word[0], count())
    for w in Words
)

科兹洛夫斯基在github上回答

关于使用这个查询对象：

char_count_pair = list(query) 
for start_char, c in char_count_pair:
    print('char:', start_char, ', count:', c)