如何将由列表组成的字符串转换为实lis

Question

现在我有了unicode对象

u'[
    [
        [
            ["Hello","w_0","w_0,w_10",1],
            [".","w_1","",0," "],
            ["This","w_2","",0," "],
        ]
        [
            ["\u4f60\u597d","w_10","w_0,w_10",1],
            ["\uff0c","w_11","",0],
            ["\u6211","w_12","",0],
        ],
        "http://www.kekenet.com/menu/201206/187574.shtml",154191
    ]
]'

如何将其转换为列表对象，如

[
    [
        [
            ["Hello","w_0","w_0,w_10",1],
            [".","w_1","",0," "],
            ["This","w_2","",0," "],
        ],
        [
            ["\u4f60\u597d","w_10","w_0,w_10",1],
            ["\uff0c","w_11","",0],
            ["\u6211","w_12","",0],
        ],
        "http://www.kekenet.com/menu/201206/187574.shtml",154191
    ],
]

Answer 1

可以使用^{}安全地计算包含Python文本的字符串。你知道吗

from ast import literal_eval

a = '["Hello", "World!", 2]'
b = literal_eval(a)
# ["Hello", "World!", 2]

请注意，字符串只能包含以下内容：字符串、字节、数字、元组、列表、dict、集合、布尔值和None（取自文档here）

Answer 2

在这种情况下，您很幸运，因为您的字符串似乎是有效的JSON，所以您可以执行以下操作：

from simplejson import json

value = u'[
    [
        [
            ["Hello","w_0","w_0,w_10",1],
            [".","w_1","",0," "],
            ["This","w_2","",0," "],
        ]
        [
            ["\u4f60\u597d","w_10","w_0,w_10",1],
            ["\uff0c","w_11","",0],
            ["\u6211","w_12","",0],
        ],
        "http://www.kekenet.com/menu/201206/187574.shtml",154191
    ]
]'

array_value = json.loads(value)

为此，它依赖于使用双引号字符串的字符串（根据json规范），即["Hello","w_0","w_0,w_10",1]而不是['Hello','w_0','w_0,w_10',1]

与使用eval的解决方案相比，它的优点是更安全。。。如果这个值来自用户输入或其他不受信任的代码，那么使用eval是非常危险的，而json是安全的。你知道吗

编辑：
正如已经指出的，发布的字符串不是有效的json。。。但我不知道是不是打字错误？你知道吗

问题是：

value = u'[
    [
        [
            ["Hello","w_0","w_0,w_10",1],
            [".","w_1","",0," "],
            ["This","w_2","",0," "],
        ] <  should be a comma here
        [
            ["\u4f60\u597d","w_10","w_0,w_10",1],