擅长:python、mysql、java
<p>这是一种方法:</p>
<pre><code>k = sorted(dt, key=dt.__getitem__)
v = sorted(dt.values())
sorted_dt_scores = zip(k,v)
</code></pre>
<p>打印<code>sorted_dt_scores</code>时输出:</p>
<pre><code>[('Ramesh', {'score': 56}), ('Manoj', {'score': 69}), ('sudha', {'score': 75}), ('Shashi', {'score': 78}), ('Resham', {'score': 95}), ('Amruta', {'score': 95})]
</code></pre>