替换C文件中的行，python

Question

我有一个C文件，其中包含以下两行：

(*Something_something_XXXName_1()) = 3.54324E+7;
(*Something_something_XXXName_2()) = 7.13123E+7;

当我运行脚本时（稍后会显示），我想用新值替换它，例如：

(*Something_something_XXXName_1()) = 1.53493E+7;
(*Something_something_XXXName_2()) = 9.12839E+7;

现在看我的python脚本

我给你一个身份证

ID_File = "anId" #imagine the ID looking like x00...
extracted_id, formated_for_cfile, x = func_name(ID_File)

这里我把值改成另一个。你知道吗

for c_file in args.cpath:
    f = open(c_file, 'r')
    c_contents = f.read()

    c_replaced_contents = re.sub(r'(.*)Something_something_XXXName_{0}\(\)\) = '.format(x+1) +
                                 '.*;(.*)', r'\Something_something_XXXName_{0}()) = '.format(x+1) +
                                 formated_for_cfile + r';\2', c_contents)
    f.close()

    with open(c_file, 'w') as c_write:
        c_write.write(c_replaced_contents)

此函数接受ID并将其拆分为两个值。正如你所看到的，它也做了两件事。从part\u str到part\u intstr=获取转换为字符串的正常int值。从str \u formated \u for \u cfile到formated \u for \u cfile，我得到了1.53493E+7和9.12839E+7

def func_name(ID):
    str_id = ID_File[1:17]
    a_str_id = ''
    for x in range(0, 2):
        part_str = str_id[8 * x:8 * (x + 1)]
        part_int = int(part_str, 16)
        part_intstr = str(part_int)

        str_formated_for_cfile = '{:.7E}'.format(part_int).replace("E+0", "E+")
        formated_for_cfile = re.sub(r'(.*)0+E(.*)', r'\1E\2',str_formated_for_cfile)

        a_str_id = a_str_id.lstrip() + " " + part_intstr
        extracted_id = list(a_str_id.split(' '))

    return extracted_id, formated_for_cfile, x

问题是没有替换C文件中的行。我错过了什么？你知道吗

下面是代码相邻的脚本（只是为了更简单的可读性）：

ID_File = "anId" #imagine the ID looking like x00...
extracted_id, formated_for_cfile, x = func_name(ID_File)

for c_file in args.cpath:
    f = open(c_file, 'r')
    c_contents = f.read()

    c_replaced_contents = re.sub(r'(.*)Something_something_XXXName_{0}\(\)\) = '.format(x+1) +
                                 '.*;(.*)', r'\Something_something_XXXName_{0}()) = '.format(x+1) +
                                 formated_for_cfile + r';\2', c_contents)
    f.close()

    with open(c_file, 'w') as c_write:
        c_write.write(c_replaced_contents)

def func_name(ID):
    str_id = ID_File[1:17]
    a_str_id = ''
    for x in range(0, 2):
        part_str = str_id[8 * x:8 * (x + 1)]
        part_int = int(part_str, 16)
        part_intstr = str(part_int)

        str_formated_for_cfile = '{:.7E}'.format(part_int).replace("E+0", "E+")
        formated_for_cfile = re.sub(r'(.*)0+E(.*)', r'\1E\2',str_formated_for_cfile)

        a_str_id = a_str_id.lstrip() + " " + part_intstr
        extracted_id = list(a_str_id.split(' '))

    return extracted_id, formated_for_cfile, x

Answer 1

正则表达式有问题。 在第一个参数中有Something_something_XXXName_{0}，但这与Something_something_XXXName_1不匹配。相反，它应该是Something_something_XXXName_\d或Something_something_XXXName_(\d+)。在第二个参数中，\S表示匹配任何非空白字符，您可能是指\1S。你知道吗

Answer 2

使用sed

sed s/'(*Something_something_XXXName_1())'/'(*Something_something_XXXName_1())=1.53493E+7;\/\/'/g file.c >new_file.c 

或者

#define NEW_VAL 1.53493E+7
sed s/'(*Something_something_XXXName_1())'/'(*Something_something_XXXName_1())=NEW_VALUE;\/\/'/g file.c >new_file.c