<p>为了实际检查文件夹是否存在,必须指定其路径并使用<code>os.path.exists</code>。困难的是嵌套列表中的字符串有时表示文件夹名,有时表示文件名。我编写了一个函数,用于测试所提供结构的成员是否存在,并尝试确定内容是否表示文件夹名称。你知道吗</p>
<pre><code>import os
folderStructure = [
['Folder1',
['subfolder1',
['sub-sub-folder1', 'sub-sub-folder2']
]
],
['Folder2',
['sub-folder2'], ['sub-folder3']
],
['Folder3',
['sub-folder4']
],
['Folder4'],
['file1', 'file2', 'file3']
]
def path_hierarchy_exists(pathslist,base_path='.'):
print pathslist,base_path
if isinstance(pathslist,basestring): # pathslist is a string that names a file
return os.path.exists(os.path.join(base_path,pathslist))
elif len(pathslist)==1: # Leaf sub-folders or leaf files
if not path_hierarchy_exists(pathslist[0],base_path):
return False
elif isinstance(pathslist[0],basestring) and isinstance(pathslist[1],list):
# pathslist is a list starting with the folder name and following with a list of folder contents
folderName = pathslist[0]
if not os.path.exists(os.path.join(base_path,folderName)): # Folder does not exist
return False
for folderContents in pathslist[1:]:
if not path_hierarchy_exists(folderContents,os.path.join(base_path,folderName)):
return False # Folder contents do not exist
else: # pathslist is a list of nested folders
for paths in pathslist:
if not path_hierarchy_exists(paths,base_path):
return False
return True
print(path_hierarchy_exists(folderStructure))
</code></pre>