我有一个充满信息的数据库,我正在尝试编写一个python脚本,它将提取一些数据并将其组织成一个报告。以下是我目前掌握的情况:
import cx_Oracle
import pandas as pd
conn = cx_Oracle.connect('REDACTED')
cursor = conn.cursor()
# Currently hard-coded to return single known motor number
cursor.execute('SELECT MOTORID FROM MOTORS WHERE SERIALNUM=804')
# Returns [(11)]
lMotorID = cursor.fetchall()
# Query Assessments for list of how long the motor had run when assessment was taken
cursor.execute("SELECT DISTINCT RUNHOURS FROM ASSESSMENTS WHERE MOTORID = %s \
ORDER BY RUNHOURS" % lMotorID[0])
# Returns [(0), (0.91), (8), (25), ...]
lHours = cursor.fetchall()
# Query for number of installed sensors by senor type
cursor.execute("SELECT SENSTYP, COUNT(STATUS) FROM HEALTH LEFT JOIN INSTRUMENTATION \
ON HEALTH.INSTROID = INSTRUMENTATION.INSTROID LEFT JOIN ASSESSMENTS \
ON HEALTH.ASSESSID = ASSESSMENTS.ASSESSID WHERE ASSESSMENTS.ASSESSID \
IN (SELECT ASSESSID FROM ASSESSMENTS WHERE MOTORID = 11 AND RUNHOURS = %s) \
GROUP BY SENSTYP ORDER BY SENSTYP" % lHours[2])
# Returns a 2-column dataframe with sensor type in column 0 and the total in column 1
dfTotal = pd.DataFrame(cursor.fetchall())
因为我想让它适用于任何电机,所以我想用一个变量替换硬编码的MOTORID = 11
。我尝试用以下内容替换上一个查询:
cursor.execute("SELECT SENSTYP, COUNT(STATUS) FROM HEALTH LEFT JOIN INSTRUMENTATION \
ON HEALTH.INSTROID = INSTRUMENTATION.INSTROID LEFT JOIN ASSESSMENTS \
ON HEALTH.ASSESSID = ASSESSMENTS.ASSESSID WHERE ASSESSMENTS.ASSESSID \
IN (SELECT ASSESSID FROM ASSESSMENTS WHERE MOTORID = %s AND RUNHOURS = %s) \
GROUP BY SENSTYP ORDER BY SENSTYP" % (lMotorID[0], lHours[2]))
dfTotal = pd.DataFrame(cursor.fetchall())
这时我得到了ORA-00936错误。我不明白为什么查询是用硬编码的值来完成的,但当值被一个变量(在前一个查询中起作用的变量)替换时就不明白了。提前谢谢。你知道吗
需要修复
cursor.execute
的语法,例如以百分号作为参数前缀对于通过python的MySQL连接是有效的,而Oracle接受冒号。你知道吗
或者另一种选择是使用有序元组:
相关问题 更多 >
编程相关推荐