下面的标志不起作用,无法剪裁形状。相反,它会创建一个矩形选择。你知道吗
self.setFlag(self.ItemClipsToShape)
如何将选择剪辑设置为形状?你知道吗
test.svg
<svg viewBox='0 0 108 95'
xmlns='http://www.w3.org/2000/svg'>
<g transform='scale(0.1)'>
<path id="p2" fill='blue' stroke='red' d='M249,699v43h211v-43h-64l-2,3l-2,4l-4,3c0,0-1,2-2,2h-4c-2,0-3,0-4,1c-1,1-3,1-3,
2l-3,4c0,1-1,2-2,2h-4c0,0-2,1-3,0l-3-1c-1,0-3-1-3-2c-1-1,0-2-1-3l-1-3c-1-1-2-1-3-1c-1,0-4,
0-4-1c0-2,0-3-1-4v-3v-3z'/>
<path id="p3" fill='blue' d='M385,593c0,9-6,15-13,15c-7,0-13-6-13-15c0-8,12-39,14-39c1,0,12,31,12,39'/>
</g>
</svg>
svg_mouse.py
from PyQt5 import QtWidgets
from PyQt5.QtSvg import QGraphicsSvgItem, QSvgRenderer
class SvgItem(QGraphicsSvgItem):
def __init__(self, id, renderer, parent=None):
super().__init__(parent)
self.id = id
self.setSharedRenderer(renderer)
self.setElementId(id)
bounds = renderer.boundsOnElement(id)
self.setPos(bounds.topLeft())
#self.setFlag(QtWidgets.QGraphicsItem.ItemIsSelectable, True) #horrible selection-box
def mousePressEvent(self, event: 'QtWidgets.QGraphicsSceneMouseEvent'):
print('svg item: ' + self.id + ' - mousePressEvent()')
super().mousePressEvent(event)
def mouseReleaseEvent(self, event: 'QtWidgets.QGraphicsSceneMouseEvent'):
print('svg item: ' + self.id + ' - mouseReleaseEvent()')
super().mouseReleaseEvent(event)
class SvgViewer(QtWidgets.QGraphicsView):
def __init__(self, parent):
super().__init__(parent)
self._scene = QtWidgets.QGraphicsScene(self)
self._renderer = QSvgRenderer()
self.setScene(self._scene)
def set_svg(self, data):
self.resetTransform()
self._scene.clear()
self._renderer.load(data)
item1 = SvgItem('p2', self._renderer)
self._scene.addItem(item1)
item2 = SvgItem('p3', self._renderer)
self._scene.addItem(item2)
def mousePressEvent(self, event: 'QtWidgets.QGraphicsSceneMouseEvent'):
print('SvgViewer - mousePressEvent()')
super().mousePressEvent(event)
def mouseReleaseEvent(self, event: 'QtWidgets.QGraphicsSceneMouseEvent'):
print('SvgViewer - mouseReleaseEvent()')
super().mouseReleaseEvent(event)
class Window(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.viewer = SvgViewer(self)
vb_layout = QtWidgets.QVBoxLayout(self)
vb_layout.addWidget(self.viewer)
img = b'''
<svg viewBox='0 0 108 95' xmlns='http://www.w3.org/2000/svg'>
<g transform='scale(0.1)'>
<a href=""><path id="p2" d='M249,699v43h211v-43h-64l-2,3l-2,4l-4,3c0,0-1,2-2,2h-4c-2,0-3,0-4,1c-1,1-3,1-3,
2l-3,4c0,1-1,2-2,2h-4c0,0-2,1-3,0l-3-1c-1,0-3-1-3-2c-1-1,0-2-1-3l-1-3c-1-1-2-1-3-1c-1,0-4,
0-4-1c0-2,0-3-1-4v-3v-3z'/></a>
<path id="p3" d='M385,593c0,9-6,15-13,15c-7,0-13-6-13-15c0-8,12-39,14-39c1,0,12,31,12,39'/>
</g>
</svg>'''
self.viewer.set_svg(img)
if __name__ == '__main__':
import sys
app = QtWidgets.QApplication(sys.argv)
window = Window()
window.setGeometry(500, 300, 600, 400)
window.show()
sys.exit(app.exec_())
我认为QGraphicsSvgItem使用边界矩形作为其形状。你知道吗
一个可能的但有效的解决方案是做QGraphicsPixmapItem所做的事情,即得到掩码并使用alpha区域返回元素的
shape()
。你知道吗请注意,我没有设置ItemClipsToShape标志,因为不需要它。
我还基于Qt implementation实现了正确的选择大纲。你知道吗
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