如何将一个非明确给定的字符串拆分为两行或多行？

Question

我目前正在使用一个Python机器人来输出带有文本的图像，但是我发现文本常常太长而无法显示。因此，我决定把字符串分成两行，这样它就可以适合我的图像。我利用枕头5.1的图像处理。你知道吗

我是Python编程的新手，我尝试过搜索如何将Python字符串拆分为两行或更多行。不幸的是，所有的结果似乎只处理明确给定的字符串（即“string”）。你知道吗

print("Ababoubian wisdom!")
ababou2 = ababou() #returns a string, how to split into two lines?
if("Ababou" in ababou2):
    ababou2 = ababou()
font = ImageFont.truetype("Arial.ttf", 14)
img = Image.new('RGB', (300, 200), color = (random.randint(0, 255),random.randint(0, 255), random.randint(0, 255)))
d = ImageDraw.Draw(img)
d.text((0, 0), ababou2, font=font) #draws text

预期结果：文本应环绕到下一行。你知道吗

Answer 1

我不确定一个文本包装器是否能帮助你，因为你需要分别画每一行。你知道吗

似乎应该计算单行中字符的最大长度，然后执行以下操作：

ababou2 = ababou() # Whats the point of assigning the same value twice? 
                   # does ababou() returns a different value each time?
if "Ababou" in ababou2:
    ababou2 = ababou()

res_text = list()
ababou2 = ababou2.split(' ') # Splits the string by space\ ' ', to a list of strings 
curr_txt = ''
for word in ababou2:
    if len(curr_txt) < MAX_CHARS_PER_LINE: # This you need to figure out
        curr_txt += ' '  + word
    else:
        res_text.append(curr_txt)
        curr_txt = word

font = ImageFont.truetype("Arial.ttf", 14)
img = Image.new('RGB', (300, 200), color = (random.randint(0, 255),random.randint(0, 255), random.randint(0, 255)))
d = ImageDraw.Draw(img)
y = 0
for line in res_text:
    d.text((0, y), line, font=font) #draws text
    y += SINGLE_ROW_SPACE # Figure out what is the distance between two rows.