用python存储信息的正确方法是什么

2024-05-19 15:05:34 发布

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我想问一下用python存储信息的正确方法是什么。像这样在类中存储数字(大多数是整数)可以吗?或者其他更好、更优化的方法。你知道吗

class Eclass:
    def __init__(self, name, pre=None, suf=None, t=None, g=None, subg=None, p=0, a=0, m=0, v=0,
                 ast=0, d=0, bd=0, bhc=0, cc=0, bc=0, bhp=0, bmp=0, hpr=0, mr=0, br=0, pr=0,
                 sr=0, fr=0, er=0, ar=0, wr=0, ar=0, dr=0, vr=0, bar=0, lbr=0, lpr=0, lsr=0,
                 lfr=0, ler=0, lar=0, lwr=0, lare=0, ldr=0, lvr=0, lear=0, sl=0, sm=0, mr=0,
                 rr=0, td=0):
        self.name = name
        self.pre = pre
        self.suf = suf
        self.t = t
        self.g = g
        self.subg = subg
        self.oi = name
        self.p = p
        self.a = a
        self.m = m
        self.v = v
        self.ast = ast
        self.d = d
        self.bd = bd
        self.bhc = bhc
        self.cc = cc
        self.bc = bc
        self.bhp = bhp
        self.bmp = bmp
        self.hpr = hpr
        self.mr = mr

        self.br = br
        self.pr = pr
        self.sr = sr
        self.fr = fr
        self.er = er
        self.ar = ar
        self.wr = wr
        self.ar = ar
        self.dr = dr
        self.vr = vr
        self.bar = bar

        self.lbr = lbr
        self.lpr = lpr
        self.lsl = lsr
        self.lfi = lfr
        self.lea = lea
        self.lai = lai
        self.lwa = lwa
        self.lae = lar
        self.ldi = ldr
        self.lvo = lvr
        self.lear = lear

        self.sl = sl
        self.sm = sm

        self.mr = mr
        self.rr = rr
        self.td = td

        self.tags = []

    def add_tags(self, *args):
        for element in args:
            self.tags.append(element)

所有这些都用于处理此类的其他函数中。你知道吗


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1楼 · 发布于 2024-05-19 15:05:34

一本字典对这件事是合适的。你知道吗

dic1 = dict(pre=None, suf=None, t=None, g=None, subg=None, p=0, a=0, m=0, v=0, ast=0)
dic1['lwa'] = 0
dic2 = {'a': 0, 'suf': None, 'pre': None, 'g': None, 'ast': 0, 'm': 0, 'p': 0, 'subg': None, 't': None, 'v': 0, 'lwa': 0}

print (dic1)
print (dic2)
print (dic1['t'])
print (dic2['lwa'])
print (dic1 == dic2)

输出:

{'a': 0, 'suf': None, 'pre': None, 'g': None, 'ast': 0, 'm': 0, 'p': 0, 'subg': None, 't': None, 'v': 0, 'lwa': 0}
{'pre': None, 'ast': 0, 'subg': None, 'a': 0, 'suf': None, 'g': None, 'm': 0, 'p': 0, 't': None, 'v': 0, 'lwa': 0}
None
0
True

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