从pytube数组produ中提取元素

Question

我试图从数组中提取元素并将其赋给变量，但它给了我以下错误：

Traceback (most recent call last):
    File "test.py", line 12, in <module>
    itag_start =  element.find(itag)
AttributeError: 'Stream' object has no attribute 'find'

这是我的密码

from pytube import YouTube
link = YouTube('http://youtube.com/watch?v=9bZkp7q19f0')
array = link.streams.all()
itag = 'itag'
mime_type='mime_type'
res='res'
counter = 0
iv = []
mt = []
re = []
    for element in array :
        itag_start =  element.find(itag)
        if itag_start != -1:
            itag_end = element.find('"', itag_start+len(itag)+2)
            itag_value = element[itag_start+len(itag)+1:itag_end+1]
            iv.insert(counter,itag_value)
        mime_type_start =  element.find(mime_type)
        if mime_type_start != -1:
            mime_type_end = element.find('"', mime_type_start+len(mime_type)+2)
            mime_type_value = element[mime_type_start+len(mime_type)+1:mime_type_end+1]
            mt.insert(counter,mime_type_value)

        res_start =  element.find(res)
        if res_start != -1:
            res_end = element.find('"', res_start+len(res)+2)
            res_value = element[res_start+len(res)+1:res_end+1]
            re.insert(counter,res_value)
         counter = counter + 1

但是如果我替换链接.streams.all（）直接输出，错误就消失了。你知道吗

[<Stream: itag="22" mime_type="video/mp4" res="720p" fps="30fps" vcodec="avc1.64001F" acodec="mp4a.40.2">,
 <Stream: itag="43" mime_type="video/webm" res="360p" fps="30fps" vcodec="vp8.0" acodec="vorbis">,
 <Stream: itag="18" mime_type="video/mp4" res="360p" fps="30fps" vcodec="avc1.42001E" acodec="mp4a.40.2">,
 <Stream: itag="36" mime_type="video/3gpp" res="240p" fps="30fps" vcodec="mp4v.20.3" acodec="mp4a.40.2">,
 <Stream: itag="17" mime_type="video/3gpp" res="144p" fps="30fps" vcodec="mp4v.20.3" acodec="mp4a.40.2">,
 <Stream: itag="137" mime_type="video/mp4" res="1080p" fps="30fps" vcodec="avc1.640028">,
 <Stream: itag="248" mime_type="video/webm" res="1080p" fps="30fps" vcodec="vp9">,
 <Stream: itag="136" mime_type="video/mp4" res="720p" fps="30fps" vcodec="avc1.4d401f">,
 <Stream: itag="247" mime_type="video/webm" res="720p" fps="30fps" vcodec="vp9">,
 <Stream: itag="135" mime_type="video/mp4" res="480p" fps="30fps" vcodec="avc1.4d401e">,
 <Stream: itag="244" mime_type="video/webm" res="480p" fps="30fps" vcodec="vp9">,
 <Stream: itag="134" mime_type="video/mp4" res="360p" fps="30fps" vcodec="avc1.4d401e">,
 <Stream: itag="243" mime_type="video/webm" res="360p" fps="30fps" vcodec="vp9">,
 <Stream: itag="133" mime_type="video/mp4" res="240p" fps="30fps" vcodec="avc1.4d4015">,
 <Stream: itag="242" mime_type="video/webm" res="240p" fps="30fps" vcodec="vp9">,
 <Stream: itag="160" mime_type="video/mp4" res="144p" fps="30fps" vcodec="avc1.4d400c">,
 <Stream: itag="278" mime_type="video/webm" res="144p" fps="30fps" vcodec="vp9">,
 <Stream: itag="140" mime_type="audio/mp4" abr="128kbps" acodec="mp4a.40.2">,
 <Stream: itag="171" mime_type="audio/webm" abr="128kbps" acodec="vorbis">,
 <Stream: itag="249" mime_type="audio/webm" abr="50kbps" acodec="opus">,
 <Stream: itag="250" mime_type="audio/webm" abr="70kbps" acodec="opus">,
 <Stream: itag="251" mime_type="audio/webm" abr="160kbps" acodec="opus">]

你知道怎么解决这个问题吗？你知道吗

Answer 1

更改您的线路：

textitag_start =  element.find(itag)

至

itag_start =  str(element).find(itag)

由语句array = link.streams.all()生成的PyTube流列表创建非引号字符串的列表元素。.find(itag)必须对字符串进行操作，这就是为什么会出现错误，PyTube列表元素不是字符串。你知道吗

使用str(element)将PyTube列表元素转换为字符串。请注意，.download语句中使用的PyTube列表元素不能用引号括起来，它们必须保留流列表中的原始格式。你知道吗