我正试图写一些代码,将计算不同的车牌,正确的格式和不正确的汽车速度。程序将在一个单独的文本文件中打印格式不正确的超速汽车。这是我刚刚得到的错误,我不知道如何解决它:
import re
distance = 200
speedlimit = 50
nonstandardReg = open("text.txt ","w")
userinput = input("Choose a car number 1 to 5")
if userinput ==('1')or(' 1')or('car1')or(' car1'):
car1 = "AD 12DER, 12:36:01, 12:36:40"
elif userinput ==('2')or(' 2')or('car2')or(' car2'):
car2 = "DE 61FE1, 02:47:01, 02:47:30"
elif userinput == ('3')or(' 3')or('car3')or(' car3'):
car3 = "AF 012GL, 04:08:32, 07:32:28"
elif userinput == ('4')or(' 4')or('car4')or(' car4'):
car4 = "TG 043WE, 08:45:23, 12:14:56"
elif userinput == ('5')or(' 5')or('car5')or(' car5'):
car5 = "TL 12AWY"
else:
print("Invalid Car")
car1Time1 =int(car1[16:18])
car1Time2 =int(car1[26:28])
car1TimeEnd = car1Time2-car1Time1
car1Speed = distance/car1TimeEnd
car2Time1 =int(car2[16:18])
car2Time2 =int(car2[26:28])
car2TimeEnd = car2Time2-car2Time1
car2Speed = distance/car2TimeEnd
car3Time1 =int(car3[16:18])
car3Time2 =int(car3[26:28])
car3TimeEnd = car3Time2-car3Time1
car3Speed = distance/car3TimeEnd
car4Time1 =int(car4[16:18])
car4Time2 =int(car4[26:28])
car4TimeEnd = car4Time2-car4Time1
car4Speed = distance/car4TimeEnd
car5Time1 =int(car5[16:18])
car5Time2 =int(car5[26:28])
car5TimeEnd = car5Time2-car5Time1
car5Speed = distance/car5TimeEnd
这是我得到的错误:
car2Time1 =(int(car2[16:18]))
ValueError: invalid literal for int() with base 10: ''
从你的评论来看,听起来你不确定你想要这个程序做什么。你可能在找这样的东西:
现在,如果他们尝试使用car5,您将遇到一个问题,因为您缩短了该选项,使其不包含计时信息。你知道吗
我不太确定这个代码是否对你有帮助,但是你应该重新设计你的代码,除非很难找到bug。你知道吗
你的代码有几个问题。一开始,这种情况
将始终计算为
True
。你应该使用相反。用
elif
语句依此类推。那么您只需要一个car
变量:您需要正确地初始化car5的
car
变量。你知道吗相关问题 更多 >
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