我写了这个剧本:
soilMod = ['ptaaco']
n = 2
soilModSplit = [soilMod[i:i+n] for i in range(0, len(soilMod), n)] # This returns ['pt', 'aa', 'co']
alphaTest = soilModSplit # I want to maintain the original list built before I remove items below. This returns ['pt', 'aa', 'co'] as well
if 'pt' in soilModSplit:
soilModSplit.remove('pt')
print soilModList # This returns ['aa', 'co']
print alphaTest # This also returns ['aa', 'co'] It's missing the original ['pt', 'aa', 'co'] and I didn't ask the script to remove it from this particular list.
出于某种原因,当我从soilModSplit中删除项(“pt”)时,它也会从alphaTest中删除该项。这是预期的结果吗?似乎任何构建在soilModSplit上的变量(在本例中为alphaTest)都依赖于对soilModSplit执行的任何操作。也许我做错了什么?有办法解决这个问题吗?你知道吗
谢谢你, 迈克
当您执行
alphaTest = soilModSplit
操作时,您不是在创建副本。只有两个名字引用同一个列表。如果要保存副本,请执行alphaTest = list(soilModSplit)
。你知道吗alphatest
只是绑定到soilModSplit
的同一列表的另一个名称。制作浅显副本:相关问题 更多 >
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