“for”循环x值？

Question

我试图让我的第二个数组以增量打印x，但是一旦case值改变，就重置为零。你知道吗

代码：

array = ['2017001677', '2017001677', '2017001621', '2017001621']
array2 = ['2017001677', '2017001621']

x = 0
for case in array:
    for case2 in array2:
        if(case == case2):
            print(case2)
            print(x)
    x = x + 1

电流输出：

2017001677
0
2017001677
1
2017001621
2
2017001621
3

期望输出：

2017001677
0
2017001677
1
2017001621
0
2017001621
1

我如何做到这一点？你知道吗

Answer 1

通过跟踪最后一次看到的值（从None开始），可以重置array中唯一值的计数器

array = ['2017001677', '2017001677', '2017001621', '2017001621']
array2 = ['2017001677', '2017001621']

last_case = None
for case in array:
    if case != last_case:
        x = 0
        last_case = case

    for case2 in array2:
        if(case == case2):
            print(case2)
            print(x)
            x = x + 1