dic和附加值检查表

Question

我有以下问题：

我有一个dict列表，想循环查看列表（临时列表），然后检查：

• 如果temp[x]和temp[y]的值dic[“z”]在distance\u值的范围内。你知道吗
• 如果没有，则在temp[x]和temp[y]之间插入一个新的dict，其中包含一个z\u值（temp[y]-temp[x]）/2），将其命名为dic\u x\u y
• 然后，用温度[x]中的dic值填充新插入的dic（dic_x_y[“t1”]、dic_x_y[“angle1”]和dic_x_y[“material”]）的剩余值

以下是包含列表和变量的数据：

    distance_value = 1000

    temp = [
    {
      "z": 1450,
      "t1": 0,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 1950,
      "t1": 25,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 12800,
      "t1": 25,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 13000,
      "t1": 15,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 25900,
      "t1": 15,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 26000,
      "t1": 10,
      "angle1": 90,
      "material": "Balsa 150"
    }]

我找了很多问题，但找不到答案。 我希望我能把我的问题说清楚，有人能帮我。 提前多谢了。你知道吗

我真的不知道如何开始，但这是我的想法，我不能去工作：

distance_value = 1000

for dic in temp: 
if "dic["z"] +1 (second element of the list) - dic["z"] < distance_value:
    new_dic = {"z": (dic["z"]+1 - dic["z"]), "t1": dic["t1"] , "angle1":dic["angle1"], "material":dic["material"] }
    temp.insert[dic["z"]+1, new_dic]

Answer 1

从我的json测试文件test.json：

[
    {
      "z": 1450,
      "t1": 0,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 1950,
      "t1": 25,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 12800,
      "t1": 25,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 13000,
      "t1": 15,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 25900,
      "t1": 15,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 26000,
      "t1": 10,
      "angle1": 90,
      "material": "Balsa 150"
    }]

python代码：

import json
with open('test.json') as f:
    temp = json.load(f)
distance_value = 1000

temp.sort(key=lambda k: k['z'])
counter = 0
Continue = True
while (Continue):
    for i in range (0,len(temp)-1):
        if(temp[i+1]['z'] - temp[i]['z'] > distance_value):
            Continue = True
            new_dic = {"z": (temp[i+1]['z'] + temp[i]['z'])/2., "t1": temp[i]['t1'], "angle1": 90, "material": temp[i]['material']}
            temp.append(new_dic)
            temp.sort(key=lambda k: k['z'])
            break
        else:
            Continue = False

temp_as_string = json.dumps(temp, sort_keys=True, indent=4, separators=(',', ': '))
print(temp_as_string)

我的输出：

[
    [
{
    "z": 1450,
    "t1": 0,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 1950,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 2628.125,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 3306.25,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 3984.375,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 4662.5,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 5340.625,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 6018.75,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 6696.875,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 7375.0,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 8053.125,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 8731.25,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 9409.375,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 10087.5,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 10765.625,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 11443.75,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 12121.875,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 12800,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 13000,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 13806.25,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 14612.5,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 15418.75,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 16225.0,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 17031.25,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 17837.5,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 18643.75,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 19450.0,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 20256.25,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 21062.5,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 21868.75,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 22675.0,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 23481.25,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 24287.5,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 25093.75,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 25900,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 26000,
    "t1": 10,
    "angle1": 90,
    "material": "Balsa 150"
}
]
[Finished in 0.096s]

逻辑如下：

1. 用条件运行while循环，我应该继续循环我的字典并检查吗？：Continue
2. 在while循环中，循环当前列表项，检查是否在任何可能的列表[i+1]['z']-列表[i]['z']大于设置的距离（这是检查循环）
3. 如果找到了，则使用中间点Z值创建一个新的dict，追加并重新排序（这非常重要），然后通过中断while循环的Continue条件来中断for循环（第一次出现时中断检查循环）
4. 在while循环的稍后阶段，当我们遍历all for循环并检查condition not found时，Continue为false，while循环中断